Question

Maria is using a coordinate plane with the axes labeled only with integers. She says that the point (−0.5, 2) cannot be plotted because halves are not numbered on the x-axis. Write a note to Maria about her misunderstanding and explain how to plot the point.

Answer 1

Answer:

The graph in the attached figure

Step-by-step explanation:

we have the point $(-0.5,2)$

To plot the x-coordinate $-0.5$ on the x-axis, we know that the number is located in the middle of the interval between the number 0 and the number -1

so

using a graphing tool

Plot the point

see the attached figure

Answer 2

Answer:

Integers ={Positive Natuaral Number +Natural numbers having negative sign behind it+Zero}

      ={------,-3,-2,-1,0,1,2,3,..........}

→Points marked on the X and Y axis on the Coordinate Plane=Integers only

→Point to be marked on the coordinate plane =(-0.5,2)

→As, points on both X and Y axis are integers only.To mark, -0.5 , mark a line between , 0 and -1,that will be ,-0.5.

→You can mark , any terminating decimal on the number line, which is marked with integers only.

→Terminating decimals are those decimals having $2^a ,\text{or}5^b, \text{or} 2^a \times 5^b$ in the denominator of a fraction.

So, to plot any terminating Decimal on the coordinate plane, you have to use property of Rational Numbers ,which is, you can find infinite number of terminating Decimal between two terminating Decimal.

→Mark -0.5 between 0 and -1 on the X axis.Similarly, mark integer 2 on the Y axis.Draw a line parallel to Y axis ,passing from (-0.5,0) and line parallel to X axis passing through (0,2).The intersection of these two lines will be required point (-0.5,2).