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3 years ago

Simplify. 3 (-125) please help!

Mathematics

2 answers:

Bezzdna [24]3 years ago

7 0

Answer:

-5

Step-by-step explanation:

∛—125=-5

pav-90 [236]3 years ago

3 0

Answer:

3/8

2+x>4

(x+3) (x-3)

Step-by-step explanation:

Hope this helps

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Suppose you have $1,950 in your savings account at the end of a certain period of time. You invested $1,700 at a 6.88% simple an

Licemer1 [7]

Answer:

He invest for 2 years.

Step-by-step explanation:

Given : Suppose you have $1,950 in your savings account at the end of a certain period of time. You invested $1,700 at a 6.88% simple annual interest rate.

To find : How long, in years, did you invest your money?

Solution :

Applying simple interest formula,

$A=P(1+r)^t$

Where, A is the amount A=$1950

P is the principal P=$1700

r is the interest rate r=6.88%=0.0688

t is the time

Substitute the values in the formula,

$1950=1700(1+0.0688)^t$

$\frac{1950}{1700}=(1.0688)^t$

$1.147=(1.0688)^t$

Taking log both side,

$\log(1.147)=\log ((1.0688)^t)$

Applying logarithmic formula, $\log a^x=x\log a$

$\log(1.147)=t\log (1.0688)$

$t=\frac{\log(1.147)}{\log (1.0688)}$

$t=2.06$

Approximately, He invest for 2 years.

5 0

3 years ago

Who could help me solve this

Monica [59]

6561 hope this helps

6 0

3 years ago

Read 2 more answers

PLEASE ANSWER I NEED HELP

lukranit [14]

It should be -11f + 5 :)

4 0

3 years ago

What is the name of the bolded part of this figure?

klemol [59]

Answer:

I am not sure, but I say Line BD A.

Step-by-step explanation:

It starts with a line, which is line BD.

hope this helps.

4 0

3 years ago

Read 2 more answers

Write a cosine function that has an amplitude of 2, a midline of 5 and a period of \frac{3\pi}{4} 4 3π .

kakasveta [241]

Given:

Amplitude = 2

Midline = 5

Period of $\dfrac{3\pi}{4}$ .

To find:

The cosine function.

Solution:

The general cosine function is:

$f(x)=A\cos(Bx+C)+D$ ...(i)

Where, |A| is amplitude, $\dfrac{2\pi}{B}$ is period, $-\dfrac{C}{B}$ is phase shift and D is the mid line.

Period of function is $\dfrac{3\pi}{4}$ . So,

$\dfrac{3\pi}{4}=\dfrac{2\pi}{B}$

$B=2\pi\times \dfrac{4}{3\pi}$

$B=\dfrac{8}{3}$

Substituting $A=2,\ B=\dfrac{8}{3},\ C=0,\ D=5$ in (i), we get

$f(x)=2\cos(\dfrac{8}{3}x+0)+5$

$f(x)=2\cos(\dfrac{8}{3}x)+5$

Therefore, the required cosine function is $f(x)=2\cos(\dfrac{8}{3}x)+5$ .

6 0

3 years ago