The weight of the new student is 27 kg.
Average weight
= total weight ÷total number of students
<h3>
1) Define variables</h3>
Let the total weight of the 35 students be y kg and the weight of the new student be x kg.
<h3>2) Find the total weight of the 35 students</h3>
<u>
</u>
y= 35(45)
y= 1575 kg
<h3>3) Write an expression for average weight of students after the addition of the new student</h3>
New total number of students
= 35 +1
= 36
Total weight
= total weight of 35 students +weight of new students
= y +x
<h3>4) Substitute the value of y</h3>
<h3>5) Solve for x</h3>
36(44.5)= 1575 +x
1602= x +1575
<em>Subtract 1575 from both sides:</em>
x= 1602 -1575
x= 27
Thus, the weight of the new student is 27 kg.
Answer: its x = 3
Step-by-step explanation:
The maximum or minimum of a quadratic function occurs at
x
=
−
b
2
a
. If
a
is negative, the maximum value of the function is
f
(
−
b
2
a
)
. If
a
is positive, the minimum value of the function is
f
(
−
b
2
a
)
.
f
min
x
=
a
x
2
+
b
x
+
c
occurs at
x
=
−
b
2
a
Find the value of
x
equal to
−
b
2
a
.
x
=
−
b
2
a
Substitute in the values of
a
and
b
.
x
=
−
−
12
2
(
2
)
Remove parentheses.
x
=
−
−
12
2
(
2
)
Simplify
−
−
12
2
(
2
)
.
Tap for more steps...
x
=
3
The maximum or minimum of a quadratic function occurs at
x
=
−
b
2
a
. If
a
is negative, the maximum value of the function is
f
(
−
b
2
a
)
. If
a
is positive, the minimum value of the function is
f
(
−
b
2
a
)
.
f
min
x
=
a
x
2
+
b
x
+
c
occurs at
x
=
−
b
2
a
Find the value of
x
equal to
−
b
2
a
.
x
=
−
b
2
a
Substitute in the values of
a
and
b
.
x
=
−
−
12
2
(
2
)
Remove parentheses.
x
=
−
−
12
2
(
2
)
Simplify
−
−
12
2
(
2
)
.
Tap for more steps...
x
=
3
4x-35=9x
-4x
-35=5x
divide by 5
x= -7
Answer:
Step-by-step explanation:
7 with exp 3 times 9 with exp 4 minus 2=
343 times 6561 minus 2=
2250421
Answer:
C. (4,-7)
Step-by-step explanation:
To answer this question, I just graphed the two equations. Then I found where they intersected.
