Ask question

Ask question

All categories

3 years ago

8

What is mMHJ? Please help

1 answer:

Ghella [55]3 years ago

7 0

2x - 20 = x + 15

x = 35

Now plug x in:

2*35 - 20 = 50 degrees

You might be interested in

How does this work hahahahaha

Leviafan [203]

Did you mean how does brainly work?

It is very simple to figure out if you need help let me know! :)

3 0

3 years ago

Read 2 more answers

If your bank charges an out-of-network service fee of $3.00, and you withdraw $20 from each of three out-of-network ATMs, how mu

kap26 [50]

It is $69 because if every time you withdraw money you get $3 and you took $20 out 3 times that 20x3 is 60 and then plus $3x3 is nine add it all together it is $69

4 0

3 years ago

Read 2 more answers

Use synthetic division to determine f(-2) for the function f (x) = 9x^3 - 18x^2 - 16x + 32

evablogger [386]

Answer: -80

Step-by-step explanation:

7 0

3 years ago

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

3 years ago

In the data set shown below, what is the value of the quartiles? {42, 43, 44, 44, 48, 49, 50} A. Q1 = 43.5; Q2 = 44; Q3 = 49 B.

ANTONII [103]

Answer:

C

Step-by-step explanation:

I don't actually know how to explain it but,

Q1=43.5

Q2=44

Q3=48.5

Sorry, I can't help more.

3 0

3 years ago