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4 years ago

What is 5/6 divided by 3/7 in simplest form

Mathematics

2 answers:

Alex777 [14]4 years ago

8 0

(5/6)/(3/7)

=5/6*7/3

=35/18

algol134 years ago

6 0

When you're dividing fractions, you've got to slip the second fraction then multiply them together. Once you've flipped it, you get
5/6 x 7/3
You then simply multiply the numerators and the denominators
5x7= 35
6x3= 18
Therefore, this becomes 35/18, which can be simplified to 1 17/18
Hope this helps :)

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Write an expression that represents the<br> perimeter of this picture frame.

Nitella [24]

Answer:

6x+2

Step-by-step explanation:

The perimeter is all of the sides added together.

We know that in a rectangle, sides that are parallel to each other are the same.

So, to find the expression that represents the perimeter, you have to multiply 2x+1 by 2 and x by 2 and add both of those together.

(2*(2x+1))+(2*(x))

(4x+2)+(2x)

4x+2+2x

6x+2

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3 years ago

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tensa zangetsu [6.8K]

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3 years ago

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el cobre tiene un punto de ebullicion de 2595°C y su temperatura de fusión es de 1083°C ¿cuál es la diferencia de temperaturas e

Vladimir79 [104]

Answer: 1512°C

Step-by-step explanation:

I will answer this in English:

The data we have: The boiling point is 2595°C and the fussion point is 1083°C

the difference between those points is equal to the direct difference between the temperatures:

Diff = 2595°C - 1083°C = 1512°C

5 0

4 years ago

A 10 ft ladder is being pulled away from a wall at a rate of 3 ft/sec. What is the rate of change in the area beneath the ladder

andriy [413]

Answer:

The rate of change in the area beneath the ladder is 5.25 ft²/s

Step-by-step explanation:

Area of triangle is given by;

$A = \frac{1}{2}bh\\\\2A = bh\\\\take \ derivative \ of \ both \ sides \ with \ respect \ to \ "t"\\\\2\frac{dA}{dt} = h\frac{db}{dt} + b\frac{dh}{dt}\\\\divide \ through \ by \ 2\\\\\frac{dA}{dt} = (\frac{h}{2} )\frac{db}{dt} + (\frac{b}{2}) \frac{dh}{dt}$

where;

b is the base of the triangle, given as 6 ft

h is the height of the triangle, determined by applying Pythagoras theorem.

h² = 10² - 6²

h² = 100 - 36

h² = 64

h = √64

h = 8 ft

Determine the rate of change of the height;

$h^2 + b^2 = 10^2\\\\h^2 + b^2 =100\\\\2h\frac{dh}{dt} + 2b\frac{db}{dt} =0\\\\h\frac{dh}{dt} + b\frac{db}{dt} =0\\\\h \frac{dh}{dt} = -b\frac{db}{dt} \\\\\frac{dh}{dt} = (\frac{-b}{h} )\frac{db}{dt}\\\\\frac{dh}{dt} =(\frac{-6}{8})(3)\\\\\frac{dh}{dt} = -\frac{9}{4} \ ft/s$

Finally, determine the rate of change of area beneath the ladder;

$\frac{dA}{dt} = (\frac{h}{2} )\frac{db}{dt} + (\frac{b}{2}) \frac{dh}{dt}\\\\\frac{dA}{dt} = (\frac{8}{2} )(3) + (\frac{6}{2}) (\frac{-9}{4})\\\\\frac{dA}{dt} = 12 - \frac{27}{4} \\\\\frac{dA}{dt} = \frac{48-27}{4}\\\\\frac{dA}{dt} = \frac{21}{4} \ ft^2/s\\\\\frac{dA}{dt} = 5.25 \ ft^2/s$