Answer :
no. of days used to repair 1250m of road = 5
no. of days used to repair 1m of road = 5/1250
no. of days used to repair 8000m of road (8*1000m ) = 5/1250*8000= 32 days
Answer:
Calculation of the distance of a wheel passed.
Step-by-step explanation:
Answer:
C is correct
Step-by-step explanation:
10x³+2x²+0x-11
+0x³+9x²+2x-2
=10x³+11x²+2x-13
The calculated average of a data set best describes A: Mean.
