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3 years ago

Can anyone help me with my homework

Mathematics

2 answers:

tatiyna3 years ago

6 0

Graph 1:

A (-9,5)
B (7,4)
C (-6,-3)
D (0,-5)
E (8,-8)
F (0,7)
G (-8,0)
H (4,0)
I (-3,-9)
J (-4,2)

Graph 2:

K (5,7)
L (0,-9)
M (1,3)
N (-7,-5)
O (7,-1)
P (0,1)
Q (2,-4)
R (-9,6)
S (-3,0)
T (9,0)

alexandr402 [8]3 years ago

3 0

Answer:

Step-by-step explanation:

Graph 1:

A=(-9,5)

B=(7,4)

C=(-6,-3)

D=(0,-5)

E=(8,-8)

F=(0,7)

G=(0,-8)

H=(0,4)

I=(-3,-9)

J=(-4,2)

Graph 2:

K=(5,7)

L=(0,-9)

M=(1,3)

N=-7,-5)

O=(7,-1)

P=(0,-1)

Q=(2,-4)

R=(-9,6)

S=(-3,0)

T=(0,9)

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Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

$\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})$

Compute the sample sizes as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}$

$n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}$

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(b)

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$\hat p_{1}=0.45\\\hat p_{2}=0.58$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}$

$n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}$

$=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666$

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