What is the decimal representation of 2/10

Mathematics

2 answers:

7nadin3 [17]3 years ago

4 0

Look at the picture.

$\dfrac{2}{10}=0.2$

ad-work [718]3 years ago

3 0

.2 is the decimal representation of 2/10

You might be interested in

May someone help me with this problem?

Katyanochek1 [597]

Answer:

$a. \: \: \frac{ {4x}^{6} }{ {y}^{3} } \\$

$b. \: \: \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$

Step-by-step explanation:

${( {4x}^{ - 2} y)}^{ - 3} \\ {4x}^{ - 2 \times - 3} \: \: {y}^{1 \times - 3} \\ {4x}^{6} {y}^{ - 3} \\ \frac{ {4x}^{6} }{ {y}^{3} } \\$

${( {8x}^{6} {y}^{ - 3}) }^{ \frac{1}{2} } \\ {8x}^{6 \times \frac{1}{2} } \: \: {y}^{ - 3 \times \frac{1}{2} } \\ {8x}^{3} {y}^{ - \frac {3}{2} } \\ \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$

7 0

2 years ago

Can anyone tell me if this is right

Rashid [163]

Answer:

yes it is correct

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Which angle measures create a triangle with three different side lengths. 40°, 40°, and 100° 65°, 65°, and 65° 45°, 45°, and 90°

Gala2k [10]

Answer:

29°, 58°, and 93°

Step-by-step explanation:

If the angles opposite are equal, the sides are equal. In order to have three different side lengths, you must have <em>three different angles</em>.

8 0

3 years ago

Solve the equation<br><br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B8%7Dx%20-%2017%20%3D%2010" id="TexFormula1" titl

Annette [7]

Answer:

x = 72

Step-by-step explanation:

<u>To solve for 'x', isolate it</u>. This means to keep 'x' on one side of the equal sign, while moving the other numbers to the other side. The numbers on the other side will tell you what 'x' equals to.

<u>When 'moving' a number to the other side, you cancel it out where it originally is by doing reverse operations</u>. (Reverse operation pairs are addition/subtraction and division/multiplication). To keep an equation balanced, <u>what you do to one side you have to do to the other</u>.

$\frac{3}{8}x-17=10$ Keep 'x' on the left and move everything over.