f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola. FYI: Different textbooks have different interpretations of the reference "standard form" of a quadratic function.
The standard form of a parabola is y=ax2++bx+c , where a≠0 . The vertex is the minimum or maximum point of a parabola. If a>0 , the vertex is the minimum point and the parabola opens upward. If a<0 , the vertex is the maximum point and the parabola opens downward.
Y= (x(9/5)) + 32; Ex: y=(100(9/5)) + 32 —> 100 x 1.8 (or 9/5) = 180–> 180 + 32= 212 F
Answer:
I’m not sure what this question is asking, but I’ll write an equation of this circle you are describing. Here, the x coordinate of the center is h, the y coordinate is k, and radius is r in the equation : (x-h)^2+(y-k)^2=r^2, meaning the equation in this situation is the following: (x-2)^2+(y-8)^2=9
Step-by-step explanation:
To solve for the midpoint of the segment we use the equation that is given as:
(x1 + x2 / 2) , (y1 + y2 / 2)
For the points given,
(x1 + x2 / 2) , (y1 + y2 / 2)
(3+ 2 / 2) , (-5 + 9 / 2)
(5/2 , 2) or (2.5 , 2)
Hope this answers the question. Have a nice day. Feel free to ask more questions.
Radius equals: 4.51
hope this helps! ♥
