Write the equation of the circle with center (−3, −2) and (4, 5) a point on the circle.
2 answers:
1. distance = √((x₂-x₁)²+(y₂-y₁)²)= radius of the circle.
distance = √((4-(-3))²+(5-(-2))7²) = √98
2. (x-k)²+(y-h)²=r² center (-3,-2) which is (k,h)
(x-(-3))²+(y-(-2))²= (√98)²
(x+3)+(y+2)² = 98 is the equation
Answer:
B. (x + 3)^2 + (y + 2)^2 = 98
Step-by-step explanation:
(x + 3)^2 + (y + 2)^2 = 98
r =(sqroot) (x − h^)2 + (y − k)^2
r =(sqroot) (4 − (−3)^2 + (5 − (−2)^2
r = (sqroot) 7^2 + 7^2
r = (sqroot) 49 + 49
r =(sqroot) 98
x^2 + y^2 = r^2
(x − (−3)^2 + (y − (−2)^2 = (sqroot) (
98)^2
(x + 3)^2 + (y + 2)^2 = 98
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