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3 years ago

X+y=3 & 8x+y=4 elimination need help

Mathematics

1 answer:

aivan3 [116]3 years ago

7 0

Hopefully you can read cursive writing (: hope this helps!

You might be interested in

-1/3x-4/3y=-2 1/3x-2/3y=4 using elimination

Minchanka [31]

-1/3x-4/3y=2

1/3x-2/3y=4

First realize that the coefficient of x is -1/3 and 1/3 which can be eliminated with addition

Adding the two equations together gets

-6/3y=6

Simplify

-2y=6

y=-3

Substitute back into original equation

1/3x-2/3(-3)=4

1/3x+2=4

1/3x=2

x=6

Answer

x=6, y=-3

Check answer

-1/3(6)-4/3(-3) =?= 2

-2+4=2

2=2

Done!

5 0

2 years ago

The relative growth rate for a certain type of mutual fund is 15% per year. An account is opened with a balance of $3,000. How m

wlad13 [49]

We have been given that an account is opened with a balance of $3,000 and relative growth rate for a certain type of mutual fund is 15% per year.

In order to tackle this problem we have to find the value of mutual fund after 5 years. For our purpose we will use compound interest formula.

$A=P(1+r)^{t}$ ,where A= amount after t years, P= principal amount, r= interest rate (decimal) and t= number of years.

After substituting our given values in above formula we will get

$A=3000(1+.15)^{5}$

Now we will solve for A

$A=3000(1+.15)^{5}=3000(1.15)^{5}\\ A=3000\cdot (2.011357187)=6034.07$

Therefore, after 5 years mutual fund is worth $6034.07.

8 0

4 years ago

T increased by r the answer

erma4kov [3.2K]

So r is a number that when you add to t it will increase so its

T + r

8 0

3 years ago

Read 2 more answers

The graph of the function y=f(x)

jarptica [38.1K]

The range is the high and low points.

So (5, 2]

5 0

3 years ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

So the diagonals measure the same, therefore this is a rectangle.

5 0

3 years ago