$\sin ^4 x \tan ^2 x = \dfrac{\sin ^4 x\ \sin ^2 x }{\cos ^2 x} = \dfrac{\sin^6 x}{\cos ^2 x} = \dfrac{(\sin ^2 x)^3}{\cos^2 x}=\dfrac{(1-\cos^2 x)^3}{\cos^2 x}$

7 0

2 years ago

Solve 2(5x + 6) < x - 15 + 9x.

ipn [44]

Answer:

Hope that was helpful for you! Good luck.

3 0

3 years ago

Erin has 4 1/2 pounds of trail mix. She wants to make 3/4 pound bags of mix for snacks. How many bags can she make?

PtichkaEL [24]

Answer:

Step-by-step explanation:

4 1/2 = 9/2=18/4

(18/4)/(3/4)=18/3=6

so she need 6 bags

4 0

2 years ago