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3 years ago

Can anyone help solve this question? I’m lost

Mathematics

1 answer:

Oksana_A [137]3 years ago

5 0

We'll start by calling the number of pigeons we started with x, because it's the unknown.

After she clapped 1/3 flew away so she was left with

(1 - 1/3) x = (2/3) x

Two flew back, so now there are

(2/3) x + 2

She clapped again and half left, half stayed, so now

(1/2) ( (2/3) x + 2 )

One came back and there were five,

(1/2) ( (2/3) x + 2 ) + 1 = 5

Solving is unraveling.

(1/2) ( (2/3) x + 2 ) = 4

(2/3) x + 2 = 8

(2/3) x = 6

x = (3/2) 6 = 9

Answer: 9 pigeons

Check: Reviewing the story, 9 -> 6 -> 8 -> 4 -> 5 good

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3 years ago

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mylen [45]

solving the equation $x^2-12x+40=0$ we get $x=6+2i\,\,and\,\,x=6-2i$

Step-by-step explanation:

Solve the equation:

$x^2-12x+40=0$

We can solve using quadratic Formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

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Putting values:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(40)}}{2(1)}\\x=\frac{12\pm\sqrt{144-160}}{2}\\x=\frac{12\pm\sqrt{-16}}{2}\\We\,\,know\,\,\sqrt{-1}=i\\ x=\frac{12\pm4i}{2}\\ x=\frac{12+4i}{2}\,\,and\,\, x=\frac{12-4i}{2}\\ x=\frac{4(3+i)}{2}\,\,and\,\, x=\frac{4(3-i)}{2}\\x=2(3+i)\,\,and\,\,x=2(3-i)\\x=6+2i\,\,and\,\,x=6-2i$

So, solving the equation $x^2-12x+40=0$ we get $x=6+2i\,\,and\,\,x=6-2i$

Keywords: Solving quadratic equation

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