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Oksi-84 [34.3K]
3 years ago
12

Subtracting polynomials

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
6 0

Answer:

7a {}^{4}  - 4a {}^{2}b {}^{2}  +  6 \\ 3a {}^{4}  + 2ab {}^{2}  + 11 \\

4a {}^{4}  - 2a - 5

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how many such tests would it take for the probability of committing at least one type i error to be at least 0.7? (round your an
drek231 [11]

The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118   .

In the question ,

it is given that ,

the probability of committing at least , type I error is = 0.7

we  have to find the number of tests ,

let the number of test be n ,

the above mentioned situation can be written as

1 - P(no type I error is committed) ≥ P(at least type I error is committed)

which is written as ,

1 - (1 - 0.01)ⁿ ≥ 0.7

-(0.99)ⁿ ≥ 0.7 - 1

(0.99)ⁿ ≤ 0.3

On further simplification ,

we get ,

n ≈ 118 .

Therefore , the number of tests are 118 .

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Answer:

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