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4 years ago

What is the simplified form of the expression?

Mathematics

1 answer:

Veronika [31]4 years ago

4 0

Question 2 options:

x33

729x29

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√(112) - √(80) / √(20) - √(28) = ?

Evgesh-ka [11]

$\large\underline{\sf{Solution-}}$

<u>We need to solve,</u>

$\dfrac{\sqrt{112}-\sqrt{80}}{\sqrt{20}-\sqrt{28}}$

We can write the above mentioned expression as,

$\sf\longmapsto\dfrac{\sqrt{2\times2\times2\times2\times7}-\sqrt{2\times2\times2\times5}}{\sqrt{2\times2\times5}-\sqrt{2\times2\times7}}$

So,

$\sf\longmapsto\dfrac{\sqrt{4\times4\times7}-\sqrt{4\times4\times5}}{\sqrt{2^2\times5}-\sqrt{2^2\times7}}$

So,

$\sf\longmapsto\dfrac{\sqrt{4^2\times7}-\sqrt{4^2\times5}}{\sqrt{2^2\times5}-\sqrt{2^2\times7}}$

Hence,

$\sf\longmapsto\dfrac{4\sqrt{7}-4\sqrt{5}}{2\sqrt{5}-2\sqrt{7}}$

Taking common in respective terms,

$\sf\longmapsto\dfrac{4(\sqrt{7}-\sqrt{5})}{2(\sqrt{5}-\sqrt{7})}$

On cancelling 4 with 2,

$\sf\longmapsto\dfrac{4\!\!\!/^{\:2}(\sqrt{7}-\sqrt{5})}{2\!\!\!/(\sqrt{5}-\sqrt{7})}$

$\sf\longmapsto\dfrac{2(\sqrt{7}-\sqrt{5})}{(\sqrt{5}-\sqrt{7})}$

Taking (-) common,

$\sf\longmapsto\dfrac{-2(\sqrt{5}-\sqrt{7})}{(\sqrt{5}-\sqrt{7})}$

So, (√5 - √7) gets cut,

<u>Hence, </u>

$\longmapsto\bf\dfrac{\sqrt{112}-\sqrt{80}}{\sqrt{20}-\sqrt{28}}=-2$

8 0

3 years ago

2 divided by -12 what is the answer?

Strike441 [17]

Answer:

-1/6

Step-by-step explanation:

When dividing 2 by -12 you would use 2 as the numerator and -12 as the denominator and then simplify it by dividing both by two to end up with -1/6

8 0

3 years ago

-3/5 divided by -1 1/10

Mila [183]

Answer:

-6

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Find the improper fraction with a denominator of 12 that is equivalent to 10 1/4

Lilit [14]

12/3=3 so 10*3 1/4*
30 3/12 simplify improperly to
30*12
360 +1
360/12

5 0

4 years ago

Which of the following represents 8 square root x5

gavmur [86]

Answer:

$5 \sqrt{8}$

6 0

3 years ago