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lord [1]
3 years ago
11

Questions – Impulse and Momentum

Mathematics
2 answers:
tino4ka555 [31]3 years ago
4 0

Answer:

the answer is A

Step-by-step explanation:

Radda [10]3 years ago
3 0
A is the correct answer
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You're going to need to be a bit more specific. What is it you're asking us?
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Writing an equation of a probably given the vertex and focus
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The equation of the vertical parabola in vertex form is written as

y=\frac{1}{4p}(x-h)^2+k

Where (h, k) are the coordinates of the vertex and p is the focal distance.

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p=1-6=-5

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1 year ago
What is the end behavior of a function that is a fraction whose polynomial numerator has a power degree than its polynomial deno
melamori03 [73]

End behavior of a polynomial function is based on the <u>degree of the function</u> and the <u>sign of the leading coefficient</u>.  

<u>Sign of the Leading Coefficient</u> determines behavior of right side:

  • Positive: right side goes to positive infinity
  • Negative: right side goes to negative infinity

<u>Degree of the function</u> determines the behavior of the left side:

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  • Even degree: left side is same direction as right side

If you have an expression in the denominator, then you must divide the denominator into the numerator. The result will have a degree and a leading coefficient.  Use the rules stated above to determine the end behavior.

For example:

y = \frac{x^{2}+2x-3}{x-1}

We can factor to get: y = \frac{(x-1)(x+3)}{(x-1)}

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Leading Coefficient of y = x + 3 is positive so right side goes to positive infinity.

Degree of  y = x + 3 is odd so left side is opposite direction of right side, which means left side goes to negative infinity.


The denominator may not divide evenly into the numerator thus leaving a remainder, but that is ok.  We can still use the rules stated above.

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4 years ago
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lys-0071 [83]
The answer is 27.001 because .001 comes before .002
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4 years ago
Help me please i need help with it!
Elina [12.6K]

I cannot see it clearly can you write the question out please so I can answer this question for you?

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