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iragen [17]
3 years ago
6

after working out for just 8 minutes,ron has burned 56 calories. how many minutes must he work out if he wants to burn 392 calor

ies
Mathematics
2 answers:
dangina [55]3 years ago
7 0
Ron would have to work out 56 minutes to burn 392 calories
iragen [17]3 years ago
3 0

Ron would have to work out 56 minutes to burn 392 calories

btw thats alot of calories i wish i could loose wieght that fast lol

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Mr.O'Brien is paid $10 per hour for the first 40 hours he works in a week. He is paid 1.5 times that rate for each hour after th
erma4kov [3.2K]


In first 40 hours he earns = 7.30 x 40 = $292
Each hour after his rate = 7.20 x 1.5 = $10.80 per hour
In extra four hours he earns = 10.80 x 4 =  $43.20 

Total earnings = $292 + $43.20 = $335.20 
Therefore you don't agree
Hoped this helped you

8 0
3 years ago
Which answer is the approximate standard deviation of the data set?
Anna35 [415]

Answer:

3.4

Step-by-step explanation:

Standard deviation of a population is defined as:

σ² = ∑(xᵢ − μ)² / n

The standard deviation of a sample is defined as:

s² = ∑(xᵢ − x)² / (n - 1)

It's not clear which one we have, so let's calculate both.

First, we must find the mean.

μ = (5+12+15+10+12+6+8+8) / 8

μ = 9.5

Now we find the squares of the differences:

(5-9.5)² + (12-9.5)² + (15-9.5)² + (10-9.5)² + (12-9.5)² + (6-9.5)² + (8-9.5)² + (8-9.5)²

= 80

Divide by n:

σ² = 80 / 8

σ² = 10

And take the square root:

σ = √10

σ ≈ 3.2

That's not one of the answers, so let's try the standard deviation of a sample instead of a population.

Instead of dividing by n, we'll divide by n-1:

s² = 80 / 7

And take the square root:

s = √(80/7)

s ≈ 3.4

So that must be it.

6 0
3 years ago
Is 7/9 greater then 8/9
maksim [4K]
No because 7/9= 0.777777777789 and 8/9= 0.888888888888889
6 0
3 years ago
What is the recursive rule for the sequence?
adoni [48]
An= -2 (an+1), a1 = 5
5 0
3 years ago
Me+You=? <br> wanna test our equation? ;3
Vika [28.1K]
Hahaha anyway thanks for the free point
5 0
3 years ago
Read 2 more answers
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