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finlep [7]
3 years ago
13

Need help with c and d please

Mathematics
1 answer:
cupoosta [38]3 years ago
8 0

Answer:

here's what I got

C. 6 x 8  

D. 12 x 16

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The mean and standard deviation when presenting results?
krek1111 [17]

Answer:

Standard deviation is a number used to tell how measurements for a group are spread out from the average (mean), or expected value. A low standard deviation means that most of the numbers are close to the average. A high standard deviation means that the numbers are more spread out.

Step-by-step explanation:

7 0
3 years ago
What is the term of a 7-term geometric series if the first term is -11 the last term is -45,056 and the common ratio is -4
shutvik [7]
I assume you mean to ask how to find the sum of the seven terms?

You have

a_2=ra_1
a_3=ra_2=r^2a_1
a_4=ra_3=r^3a_1
...
a_7=ra_6=r^6a_1

So the sum is

a_1+ra_1+r^2a_1+\cdots+r^6a_1=a_1(1+r+r^2+\cdots+r^6)=a_1\times\dfrac{1-r^7}{1-r}

You know that a_1=-11 and r=-4, so the sum is equal to

-4\times\dfrac{1-(-4)^7}{1-(-4)}=-13108
8 0
3 years ago
Suppose that the pages per book in a library are normally distributed with an unknown mean and standard deviation. The book leng
Elanso [62]

Answer:

A t-score of 2.0244 should be used to find the 99% confidence interval for the population mean

Step-by-step explanation:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 39 - 1 = 38

Now, we have to find a value of T, which is found looking at the t table, with 38 degrees of freedom(y-axis) and a confidence level of 0.99(t_{99}). So we have T = 2.0244.

A t-score of 2.0244 should be used to find the 99% confidence interval for the population mean

6 0
3 years ago
PLEASE HELP!!!! The problem is in the photo below.
Oksi-84 [34.3K]
I believe the answer is 1.343 x 10^5
3 0
2 years ago
Suppose that the bacteria in a colony grow unchecked according to the Law of Exponential Change. The colony starts with 1 bacter
inn [45]

Answer: There are 2.25×10³⁴ bacteria at the end of 24 hours.

Step-by-step explanation:

Since we have given that

Number of bacteria initially = 1

It triples in number every 20 minutes.

So, \dfrac{20}{60}=\dfrac{1}{3}

So, our equation becomes

y=y_0e^{\frac{1}{3}k}\\\\3=1e^{\frac{1}{3}k}\\\\\ln 3=\dfrac{1}{3}k\\\\k=\dfrac{1.099}{0.333}=3.3

We need to find the number of bacteria that it will contain at the end of 24 hours.

So, it becomes,

y=1e^{24\times 3.3}\\\\y=e^{79.1}\\\\y=2.25\times 10^{34}

Hence, there are 2.25×10³⁴ bacteria at the end of 24 hours.

3 0
3 years ago
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