The lengths of the sides of the triangle are 8, 8, 20
Explanation:
Given that the perimeter of an isosceles triangle is 36 inches.
The base of the triangle is
times longer than each of its legs.
We need to determine the lengths of the sides of the triangle.
<u>Lengths of the sides:</u>
Let x denote the lengths of the sides of the triangle.
The base of the triangle is given by

Perimeter of the isosceles triangle = Sum of the three sides of the triangle.
Thus, we have,



Thus, the length of the sides of the isosceles triangle is 8 inches.
Base of the triangle = 
Hence, the three sides of the isosceles triangle are 8, 8, 20
1/3(6x-12y)
2x - 4y
the answer is A
Circumference is diameter times pi, diameter is radius times 2. The answer should be 57 inches.
Answer:
1/2.
Step-by-step explanation:
f(x) = (1/8)^x
when x = 1/3
f(x) = (1/8)^1/3
f(x) = ∛(1/8)
f(x) = 1 / ∛8
f(x) = 1/2.
Answer: −
2 x -12
Step-by-step explanation:
its already simplifed foo