Answer:
The percentage increase in Jayana's postcard collection is 15%
Step-by-step explanation:
Jayana had 20 postcards last year
With 3 more postcards this year
From the given equation Quantity = Percent x Whole
Here;
Let P = Percent/100%
Quantity = Increment in postcard = 3 postcards
Whole = The total postcards from last year = 20 postcards
Hence,
3 postcards = P x 20 postcards
P = 3/20 = 0.15
Recall P = Percent/100%
∴ Percent = P x 100% = 0.15 x 100% = 15%
The percentage increase in Jayana's postcard collection is 15%
Answer:
The correct answer is A.
A) The IQR of Karla's data in 13.
Step-by-step explanation:
The interquartile range can be defined as the difference of upper quartile and lower quartile range. If we want to find the IQR from the box plot, we can simply see the length of the box from the box plot, as it represent the IQR.
We can clearly see that:
IQR of Steve's data is 45 - 31 = 14, hence the second statement is incorrect
IQR of Karla's data is 52 - 39 = 13, hence the first statement is CORRECT
The difference of medians is 43 - 36 = 7
Hence the difference of medians is not the half or twice of IQR ranges of both data sets
It is given that batteries come in a packs of 4. It means in each pack there are 4 batteries.
Joe used 58 batteries . So to find the total number of packets of batteries joe has to open is
Number of batteries used / Total number of batteries in each packet
= 58 / 4
= 14.5
The number of battery can not be in decimal. So we will round the answer to integer. If we round it to 14 it means 14 packets. But in 14 packets there are 14*4 = 56 batteries .
But we know that Joe used 58 batteries. So we will round the final answer to 15.
It means Joe has to open 15 packets of batteries.
Would it be 61 ? i think i might be wrong
Answer:
Toyota like my mom hajaha
