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2 years ago

Please anyone help me on this...

Mathematics

2 answers:

OLga [1]2 years ago

7 0

Answer:

The 2nd choice ( the one that starts with square root of 5 )

Step-by-step explanation:

I turned all of the choices into decimals so they had the same playing field then I put them from least to greatest and I got square root of five, 5/2, 2.717171717171, 2 and 3/4.

dolphi86 [110]2 years ago

6 0

It’s answer number 2

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Determine the sum: 21.6 x 10^4 + 5.2 x 10^7. Write your answer in scientific notation.

lana [24]

Answer:

It's D

Step-by-step explanation:

Hope this helps :))

6 0

2 years ago

Given that the average rate of change for y = f(x) over the interval [0,3] is −1, the average rate of change over the interval [

Svet_ta [14]

Answer:

Answer is 2

Step-by-step explanation:

We know that average rate of change of a function f(x) in the interval (a,b) is

$\frac{1}{b-a} \int\limits^a_b {f(x)} \, dx$

Using this we can say that

$\int\limits^0_3 {f(x)} \, dx =-1(3)=-3\\\int\limits^2_3 {f(x)} \, dx =5(1)=5\\\\\int\limits^2_6 {f(x)} \, dx =4(5)=20\\$

Using properties of integration we have

3 to 6 integral = 20-5 =15

0 to2 integral = -3=5 =-8

Thus integral form 0 to 6 would be = -8+15+5 = 12

Average rate of change form 0 to 6 = $\frac{12}{6} =2$

Answer is 2

7 0

2 years ago

Find the solutions for a triangle with a = 16, c =12, and B = 63º.

maks197457 [2]

Answer:

b. A = 71.6°; C = 45.40°; b =15.0

Step-by-step explanation:

The missing values can be found with the help of the Law of Cosine and properties of triangles:

Side b (Law of Cosine)

$b = \sqrt{a^{2}+c^{2}-2\cdot a \cdot c \cdot \cos B}$

$b = \sqrt{16^{2}+12^{2}-2\cdot (16)\cdot (12) \cdot \cos 63^{\circ}}$

$b \approx 15.022$

Angle A (Law of Cosine)

$\cos A = -\frac{a^{2} - b^{2}-c^{2}}{2\cdot b \cdot c}$

$\cos A = - \frac{16^{2}-15.022^{2}-12^{2}}{2\cdot (15.022)\cdot (12)}$

$\cos A = 0.315$

$A= \cos^{-1} 0.315$

$A \approx 71.639^{\circ}$

Angle C (Sum of internal angles in triangles)

$C = 180^{\circ} - 63^{\circ} - 71.639^{\circ}$

$C = 45.361^{\circ}$

Hence, the right answer is B.

6 0

3 years ago

An animal shelter has a bin filled with 456 pounds of dog food there are 4 large dogs at the shelter who each eat 2 pounds of th

Y_Kistochka [10]

If there are 4 dogs and they each eat 2 pounds of food each day. Then, all together there are 8 pounds of food getting eaten each day. You will want to divide 456 by 8.

456/8= 57 days.

456 punds of dog food will last 57 days for 4 dogs.

7 0

2 years ago

What is the mass of an object that has a density of 1.3 g/cm3 and a volume

tangare [24]

Answer:

The mass of the object is 2.6 grams

Step-by-step explanation:

The density of an object is the ratio between its mass and its volume

The equation of the is d = $\frac{m}{V}$ , where

m is the mass

V is the volume

Let us use this equation to solve the question

∵ An object has a density of 1.3 g/cm³

∴ d = 1.3 g/cm³

∵ Its volume is 2 cm³

∴ V = 2 cm³

→ Substitute them in the equation of the denisty above

∵ 1.3 = $\frac{m}{2}$

→ Multiply both sides by 2

∴ 2 × 1.3 = 2 × $\frac{m}{2}$

∴ 2.6 = m

∴ The mass of the object is 2.6 grams

8 0

2 years ago

Please anyone help me on this...​

Please anyone help me on this...