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KIM [24]
3 years ago
15

A quantity of a gas has an absolute pressure of 400 kPa and an absolute temperature of 110 degrees kelvin. When the temperature

of the gas is raised to 235 degrees kelvin, what's the new pressure of the gas? (Assume that there's no change in volume.)
A. 854.46 kPa
B. 3.636 kPa
C. 1.702 kPa
D. 510 kPa
A. 854.46 kPa
B. 3.636 kPa
C. 1.702 kPa
D. 510 kPa
A. liquid to a solid.
B. liquid to a gas.
C. gas to a solid.
D. gas to a liquid
Biology
1 answer:
VMariaS [17]3 years ago
5 0

Answer:  The new pressure of the gas is (A) 854.46 kPa.

The pressure of a given mass of gas at the absolute temperature 110 degrees K is 400 kPa.

The temperature is raised to 235 degrees K  with constant volume.

Therefore,

Initial pressure P_{1}=400kPa

Initial temperature T_{1}=110K

Final temperature T_{2}=235K

Final pressureP_{2}=?

According to pressure law of gas,

\frac{P_{1} }{T_{1} }=\frac{P_{2} }{T_{2} }     ( at constant volume)P_{2}=\frac{P_{1}T_{2} }{T_{1} }

P_{2}=\frac{400X235}{110}

P_{2}=854.46kPa

Thus, the required new pressure of the gas is 854.46 kPa.

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