Question

Write the equation of a line perpendicular to y = -5/6x -3 and whose y-intercept is (0,11). I fr need help..

Answer 1

Hey!

A perpendicular line has the slope as the negative reciprocal of the given line, so therefore the new lines slope would be...

y = 6/5x + b

Now to find the y-intercept you will have to just plug in the given point/coordinate in the equation above and solve for b...

11 = 6/5(0) = b

11 = b

Put the given slope and y-intercept in a slope intercept form equation (slope intercept form is y = mx + b)...

y = 6/5x + 11

This new equation is:

1) perpendicular to the given equation

2) in slope intercept form

Answer: y = 6/5x + 11

Hope this Helped!

~A