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2 years ago

3. Daniel is a very good television salesperson. His annual sales average at $187,400. His

Mathematics

1 answer:

Stolb23 [73]2 years ago

4 0

Answer:

$96,220

Step-by-step explanation:

Daniel is a very good sales person

His annual sales average is $187,400

His commission on sales is 30%

= 30/100

= 0.3

His annual base salary is $40,000

Therefore, Daniel's annual gross income can be calculated as follows

Annual gross income= Annual base salary + Commission on sales

= $40,000 + (30/100 × $187,400)

= $40,000 + 0.3×$187,400

= $40,000+$56,220

= $96,220

Hence Daniel's annual gross income is $96,220

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Read 2 more answers

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BlackZzzverrR [31]

No idea what the previous part of the problem is, but you have

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which is valid for $\left|-\dfrac{x^2}4\right|$ , or $|x|$ . So the integral from 0 to 2 is

$\displaystyle\int_0^2f(x)\,\mathrm dx=\int_0^28\sum_{n\ge0}\left(-\frac14\right)^nx^{2n}\,\mathrm dx$
$=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\int_0^2x^{2n}\,\mathrm dx$

Note that since the power series only converges on the interval if $x$ is strictly less than 2, which means we have to treat this as an improper integral.

$=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\lim_{t\to2^-}\int_0^tx^{2n}\,\mathrm dx$ [/tex]
$=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\lim_{t\to2^-}\frac{x^{2n+1}}{2n+1}\bigg|_{x=0}^{x=t}$
$=\displaystyle8\sum_{n\ge0}\frac{(-1)^n}{2^{2n}(2n+1)}\lim_{t\to2^-}t^{2n+1}$
$=\displaystyle16\sum_{n\ge0}\frac{(-1)^n}{2n+1}$
$=16-\dfrac{16}3+\dfrac{16}5-\dfrac{16}7+\dfrac{16}9+\cdots$