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3 years ago

Find the length of a line segment with endpoints of –9 and 7.

Mathematics

1 answer:

madreJ [45]3 years ago

7 0

Answer:

c 16

Step-by-step explanation:

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What is the length of the hypotenuse of the triangle

kotegsom [21]

On all sides of a triangle it’s about 7 inches

7 0

2 years ago

Nick cut a circular cookie into 5 equal slices. what is the angle measure of each slice?

NemiM [27]

Answer:

72°

Step-by-step explanation:

The cookie has a shape of a circle. A circle is the locus of a point such that its distance from a point (center) is always the same. The sum of angles around the circle center is 360°.

Let x be the measure of the angle in each slice. Therefore the sum of the total 5 slice is:

x + x + x + x + x = 360

5x = 360

Dividing through by 5:

5x / 5 = 360 / 5

x = 72°

Each slice has an angle measure of 72°

5 0

2 years ago

The general form of a circle is given as x^2+y^2+4x - 12y + 4 = 0. A) What are the coordinates of the center of the circle? B) W

Alex_Xolod [135]

Answer:

center = (-2, 6)

radius = 6

Step-by-step explanation:

Equation of a circle

$(x-a)^2+(y-b)^2=r^2$

(where (a, b) is the center and r is the radius)

Therefore, we need to rewrite the given equation into the standard form of an equation of a circle.

Given equation:

$x^2+y^2+4x-12y+4=0$

Collect like terms and subtract 4 from both sides:

$\implies x^2+4x+y^2-12y=-4$

Complete the square for both variables by adding the square of half of the coefficient of $x$ and $y$ to both sides:

$\implies x^2+4x+\left(\dfrac{4}{2}\right)^2+y^2-12y+\left(\dfrac{-12}{2}\right)^2=-4+\left(\dfrac{4}{2}\right)^2+\left(\dfrac{-12}{2}\right)^2$

$\implies x^2+4x+4+y^2-12y+36=-4+4+36$

Factor both variables:

$\implies (x+2)^2+(y-6)^2=36$

Therefore:

center = (-2, 6)
radius = √36 = 6

7 0

1 year ago

Find the area of the triangle with the given base and height. b = 3 m and h = 10 1/2 m

svetoff [14.1K]

Statement:

The base of a triangle is 3m and its height is $10 \frac{1}{2}$ m.

To find out:

The area of the triangle.

Solution:

Given, base = 3m, height = $10 \frac{1}{2}$ m
We know,

$\sf \: area \: \: of \: \: a \: \: triangle = \frac{1}{2} \times base \: \times height$

Therefore, the area of the triangle

$\sf = (\frac{1}{2} \times 3 \times 10 \frac{1}{2} ) {m}^{2} \\ \sf = ( \frac{1}{2} \times 3 \times \frac{21}{2} ) {m}^{2} \\ = \sf \frac{63}{4} {m}^{2} \\ = \sf 15\frac{3}{4} {m}^{2}$