Using fluorescent imaging techniques, researchers observed that the position of binding sites on HIV peptides is approximately N
1 answer:
You might be interested in
Answer:
The difference in the sample proportions is not statistically significant at 0.05 significance level.
Step-by-step explanation:
Significance level is missing, it is α=0.05
Let p(public) be the proportion of alumni of the public university who attended at least one class reunion
p(private) be the proportion of alumni of the private university who attended at least one class reunion
Hypotheses are:
: p(public) = p(private)
: p(public) ≠ p(private)
The formula for the test statistic is given as:
z= where
- p1 is the sample proportion of public university students who attended at least one class reunion (
)
- p2 is the sample proportion of private university students who attended at least one class reunion (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the alumni from public university (1311)
- n2 is the sample size of the students from private university (1038)
Then z= =-0.207
Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.
Answer:
36 milliliters of rain.
Step-by-step explanation:
The rate at which rain accumluated in a bucket is given by the function:
Where r(t) is measured in milliliters per minute.
We want to find the total accumulation of rain from <em>t</em> = 0 to <em>t</em> = 3.
We can use the Net Change Theorem. So, we will integrate function <em>r</em> from <em>t</em> = 0 to <em>t</em> = 3:
Substitute:
Integrate:
Evaluate:
36 milliliters of rain accumulated in the bucket from time <em>t</em> = 0 to <em>t</em> = 3.
m = -9!
Proof:
⭐ Please consider brainliest! ⭐
✉️ If any further questions, inbox me! ✉️