Question

Using fluorescent imaging techniques, researchers observed that the position of binding sites on HIV peptides is approximately Normally distributed with a mean of 2.45 microns and a standard deviation of 0.35 micron. What is the standardized score for a binding site position of 2.03 microns? (Enter your answer rounded to one decimal place.)

Answer 1

Answer:

The values is  

Step-by-step explanation:

From the question we are told that

  The population mean is  $\mu = 2.45$

    The  standard deviation is  $\sigma = 0.35 \ mi$

     The random value is  $x = 2.03$

The standardized score for a binding site position of 2.03 microns is mathematically represented as

       $z-score = \frac{x - \mu}{ \sigma }$

=>      $z-score = \frac{2.03 - 2.45}{ 0.35}$

=>    $z-score = -1.2$