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Anarel [89]
3 years ago
6

Solve the equation3x +5 = 20Pls​

Mathematics
2 answers:
GREYUIT [131]3 years ago
7 0

Answer:

x = 5.

Step-by-step explanation:

3x +5 = 20

Subtract 5 from both sides:

3x + 5 - 5 = 20 - 5

3x = 15

Divide both sides by 3:

x = 15/3

x = 5.

Tasya [4]3 years ago
3 0

Answer:

<h2>x = 5</h2>

Step-by-step explanation:

3x+5=20\qquad\text{subtract 5 from both sides}\\\\3x+5-5=20-5\\\\3x=15\qquad\text{divide both sides by 3}\\\\\dfrac{3x}{3}=\dfrac{15}{3}\\\\x=5

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dalvyx [7]

Answer:

x intercept= (-3,0)  y intercept= (0,3)

Step-by-step explanation:

for x intercepts, y should equal zero

for y intercepts, x should equal zero

x intercept: -x+0=3

-x=3

x=-3  (x,y)--> (-3,0)

y intercept: 0+y=3

y=3 (x,y)--> (0,3)

4 0
2 years ago
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How many repeating digits are in 0 536?
Inga [223]
Are there any repeating digits? There isn’t. Remember, on a device make sure you put 3 dots next to a decimal to show it’s repeating.
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2 years ago
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A research scientist wants to know how many times per hour a certain strand of bacteria reproduces. The mean is found to be 9.8
svetlana [45]

Answer:

The 99% confidence interval for the true mean number of reproductions per hour for the bacteria is between 9.6 and 10.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{2.4}{\sqrt{955}} = 0.2

The lower end of the interval is the sample mean subtracted by M. So it is 9.8 - 0.2 = 9.6 reproductions per hour.

The upper end of the interval is the sample mean added to M. So it is 9.8 + 0.2 = 10 reproductions per hour.

The 99% confidence interval for the true mean number of reproductions per hour for the bacteria is between 9.6 and 10.

8 0
2 years ago
54 kilometers equal – metres.​
Xelga [282]

\huge\mathfrak\blue{AnSwEr}

\sf{54 \: km \:  =  54000 \: meters}

5 0
3 years ago
Letang Industrial Systems Company (LISC) is trying to decide between two different conveyor belt systems. System A costs $280,00
Vanyuwa [196]

We have to calculate the EAC for both the conveyor belt system.

Solutions :

<u>Equivalent Annual Cost or (EAC) for the SYSTEM-A</u>

$\text{Operating cash flow } = \text{Pre-tax annual operating cost (1-tax rate )} + (\text{depreciation expense} \times $tax rate )

                                $=-855,000(1-0.23)+\left[\left(\frac{280,000}{4}\right)\times 0.23\right]$

                               $= (-85,000 \times 0.77 ) + (70,000 \times 0.23)$

                               = $ 49,350

Year      Annual Cost flow     Present value factor    Present Value of Annual

                                                     at 10%                              cash flow

1                    -49,350                  0.909091                          -44,863.64

2                  -49,350                   0.826446                          -40,785.12

3                   -49,350                  0.751315                            -37,077.39

4                   -49,350                 <u> 0.683013   </u>                       <u>-33,706.71  </u>

     Total                                    $ 3.169865                       $ -156,432.86  

Therefore, Net Present value = present value of the annual cash flow - initial investment.

           = 156,432.86 - 280,000

          = $ 436,432.86 (negative)

Now the EAC or the Equivalent Annual Cost for System A :

$\text{EAC}= \text{Net present value / (PVIFA 10 percent, 4 years)}$

        $=\frac{436,432.86}{3.169865}$

        $= 137,681.86 $ dollar (negative)

$\text{Operating cash flow } = \text{Pre-tax annual operating cost (1-tax rate )} + (\text{depreciation expense} \times $tax rate)

$=79,000(1-0.23)+\left[\left(\frac{360,000}{6}\right) \times 0.23\right]$

$=(-78,000 \times 0.77)+(60,000 \times 0.23)$

= -$ 47,030

Year      Annual Cost flow     Present value factor    Present Value of Annual

                                                     at 10%                              cash flow

1                    -47,030                  0.909091                          -42,754.55

2                  -47,030                   0.826446                          -38,867.77

3                   -47,030                  0.751315                           -35,334.34

4                   -47,030                 0.683013                            -32,122.12

5                  -47,030                  0.620921                            -29,201.93

6                  -47,030                 <u> 0.564474  </u>                        <u>  -26,547.21 </u>  

    Total                                     $ 4.355261                       $  -204,827.91

Net Present Value = Present Value of annual cash inflows – Initial Investment

$= 204,827.91 - 360,000$

= -$ 564,827.91 (negative)

EAC for system B:

Equivalent Annual Cost for system B $=\frac{\text{net present value}}{\text{PVIFA 10 \text percent, 6 years}}$

$=\frac{-564,827.91}{4.355261}$

= -$129,688.66 (negative)

7 0
2 years ago
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