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Alecsey [184]
3 years ago
14

I need help with 8,9 and 10

Mathematics
1 answer:
rodikova [14]3 years ago
8 0

Answer:

Answer 8: D

Answer 9: A

Step-by-step explanation:

8D: 5(12)/4-1=14

9A: Plug in -5(1)+2 = -3, so the point is (1,-3)

Question 10 is not visible

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Answer:

x=-3,  x=1,  x=8

Step-by-step explanation:

When you have to find the zero of an equation like (x+3) all you have to do is solve for x.

x+3=0           equal the equation to zero

x+3-3=0-3    cancel out 3

x=-3              answer


If you have to find the zero of an equation like f(x)=-2x^2 - 5x + 7 then you would have to factor the equation.

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-2x (x - 1)   -7 (x - 1)   factor

(x - 1)   (-2x - 7)    rewrite

1st: x - 1 = 0

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2nd: -2x - 7= 0

        -2x - 7 + 7 = 0 + 7

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NO LINKS!!! PLS HELP ME IM TRYING TO GRADUATE PLSSS !!! Find the midpoint of the segment below and enter its coordinates as an
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Answer:

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Step-by-step explanation:

<em>r's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>finding</em><em> </em><em>midpoint</em><em> </em><em>=</em><em>.</em><em>(</em><em> </em><em>X1</em><em> </em><em>+</em><em> </em><em>X</em><em>2/</em><em>)</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>(</em><em>Y1+</em><em>Y2)</em><em>/</em><em>2</em>

<em>=</em><em>></em><em> </em><em>putting</em><em> </em><em>the </em><em>value</em><em> </em><em>of </em><em>in </em><em>formula</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>x=</em><em> </em><em> </em><em>4</em><em>+</em><em>1</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>y </em><em>=</em><em> </em><em>-</em><em>1</em><em>-</em><em>6</em><em>/</em><em>2</em>

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<em>hope</em><em> it</em><em> helps</em>

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