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Alecsey [184]
3 years ago
14

I need help with 8,9 and 10

Mathematics
1 answer:
rodikova [14]3 years ago
8 0

Answer:

Answer 8: D

Answer 9: A

Step-by-step explanation:

8D: 5(12)/4-1=14

9A: Plug in -5(1)+2 = -3, so the point is (1,-3)

Question 10 is not visible

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Can someone help me with this question please.
poizon [28]

Answer:

98

Step-by-step explanation:

3 bed house= 33 rooms

4 bed house 40 rooms

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8 0
3 years ago
Y=x^2-6x+3 help write the vertex form of the equation
Artist 52 [7]

Answer:

y=(x-3)^2-6

Step-by-step explanation:

y=x^2-6x+3

This is written in the standard form of a quadratic function:

y=ax^2+bx+c

where:

  • ax² → quadratic term
  • bx → linear term
  • c → constant

You need to convert this to vertex form:

y=a(x-h)^2+k

where:

  • (h,k) → vertex

To find the vertex form, you need to find the vertex. For this, use the equation for axis of symmetry, since this line passes through the vertex:

x=-\frac{b}{2a}

Using your original equation, identify the a, b, and c terms:

a=1\\\\b=-6\\\\c=3

Insert the known values into the equation:

x=-\frac{(-6)}{2(1)}

Simplify. Two negatives make a positive:

x=\frac{6}{2} =3

X is equal to 3 (3,y). Insert the value of x into the standard form equation and solve for y:

y=3^2-6(3)+3

Simplify using PEMDAS:

y=9-18+3\\\\y=-9+3\\\\y=-6

The value of y is -6 (3,-6). Insert these values into the vertex form:

(3_{h},-6_{k})\\\\y=a(x-3)^2+(-6)

Insert the value of a and simplify:

y=(x-3)^2-6

:Done

6 0
3 years ago
If ƒ (x ) = 2x 2 + 3, find ƒ (3).
dimulka [17.4K]

Answer:

f(x) = 2 \times 2 + 3 \\ f(3) = 4  + 3 \\ 3f = 7 \\ f =  \frac{7}{3}

<h2>Hope it help you</h2>
3 0
3 years ago
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Given that f (x) = x^2 - 5x and g (x) x + 4
velikii [3]
1) (x-2)^2
2)-4x(x+5)

pls mark as brainliest:))
8 0
3 years ago
The functions fand g are defined as follows.
Rudik [331]

Answer:

hi

Step-by-step explanation:

hi how are you doing?

5 0
3 years ago
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