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Iteru [2.4K]
3 years ago
6

Hi :) anyone able to teach this? I don’t understand the question , thanks in advance!

Mathematics
1 answer:
puteri [66]3 years ago
7 0

a) 62.855m

We will need to use the Pythagorean Theorem here, as we know a and c, but not b. I have attached an image of a triangle sketch to set up the problem, which should hopefully help us to visualize this problem a bit better.

Pythagorean Theorem: a^2 + b^2 = c^2

(19.8)^2 + b^2 = (65.9)^2

392.04 + b^2 = 4342.81

b^2 = 3950.77

b = 62.855 (rounded to 3 places)

b) m = 0.315

The gradient is also known as the slope. I've shown what the points would be in the image attached. Now that we know the value of b (x in the points in image), we can use points E and C to find the slope.

Point 1: (0,0)

Point 2: (62.855, 19.8)

m = (19.8 - 0) / (62.855 - 0)

m = 19.8 / 62.855

m = 0.315 (rounded to three places)

c) 17.485 degrees

The angle of inclination would be angle C. To find angle C, we will need to use an inverse trigonometry function. Any can be used since we know all of the side lengths, but I will show Sine here, opposite / hypotenuse.

sin(x) = 19.8 / 65.9

x = sin^-1 (19.8/65.9)

x = 17.485 degrees (rounded to 3 places)

Hope this helps!! :)

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\angle AOB and \angle BOC are linear pair angles.

\therefore m\angle AOB + m\angle BOC = 180° \\  \therefore  \: 3x + 124 \degree + 6x + 29 \degree  = 180° \\  \therefore  \: 9x  + 153 \degree  = 180°  \\ \therefore  \: 9x  = 180°  - 153 \degree   \\ \therefore  \: 9x  = 27 \degree   \\ \therefore  \:x =  \frac{27 \degree }{9}  \\  \huge \pink{ \boxed{\therefore  \:x =3 \degree }} \\  \\  \because \: m\angle BOC =6x + 29 \degree   \\ \therefore \: m\angle BOC =6 \times3 \degree + 29 \degree   \\ \therefore \: m\angle BOC = 18\degree + 29 \degree    \\ \\   \huge \red{ \boxed{\therefore \: m\angle BOC = 47 \degree   }}

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