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3 years ago

5m+7/2=-2m+5/2 What's m?

Mathematics

1 answer:

viktelen [127]3 years ago

3 0

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Yuson must complete 30 hours

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Answer:

Yuson Has Left After 15 Days

Step-by-step explanation:

30/2 = 15

30/2 = x = 15

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Assume that the lines that appear to be tangent are tangent O is the center of the circle find the value of X m < P= 26 a. 11

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That's hard and i need help on it too

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How to solve x^2-7=-x^2+1

andreev551 [17]

Answer:

Step-by-step explanation:

x^2 and -x^2 would cancel

and then it would be -7 = 1

it would be no solution

but I don't know, someone can prove me wrong I may have a lapse in my algebra at the moment

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3 years ago

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4 years ago

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If α and β are the zeroes of the polynomial 6y 2 − 7y + 2, find a quadratic polynomial whose zeroes are 1 α and 1 β .

ollegr [7]

Answer:

$2y^2-7y+6=0$

Step-by-step explanation:

We are given that $\alpha$ and $\beta$ are the zeroes of the polynomial $6y^2-7y+2$

$y^2-\frac{7}{6}y+\frac{1}{3}$

We have to find a quadratic polynomial whose zeroes are $1/\alpha$ and $1/\beta$ .

General quadratic equation

$x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes$

We get

$\alpha+\beta=\frac{7}{6}$

$\alpha \beta=\frac{1}{3}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2$

$\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}$

$\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3$

Substitute the values

$y^2-(7/2)y+3=0$

$2y^2-7y+6=0$

Hence, the quadratic polynomial whose zeroes are $1/\alpha$ and $1/\beta$ is given by

$2y^2-7y+6=0$

4 0

3 years ago