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aksik [14]
1 year ago
10

Given the measure of three angles in a quadrilateral, find the measure of the fourth angle.1. 40 degree , 120 degree , 100 degre

e , _____2. 73 degree, 107 degree, 122 degree
Mathematics
1 answer:
Veronika [31]1 year ago
7 0

Recall that the interior angles of a quadrilateral add up to 360 degrees.

1) Let x be the measure of the missing angle, then we can set the following equation:

40^{\circ}+120^{\circ}+100^{\circ}+x=360^{\circ}.

Solving for x we get:

\begin{gathered} 260^{\circ}+x=360^{\circ}, \\ x=100^{\circ}\text{.} \end{gathered}

2) Let y be the measure of the missing angle, then we can set the following equation:

73^{\circ}+107^{\circ}+122^{\circ}+y=360^{\circ}\text{.}

Solving for y we get:

\begin{gathered} 302^{\circ}+y=360^{\circ}, \\ y=58^{\circ}\text{.} \end{gathered}

Answer:

1) 100 degrees.

2) 58 degrees.

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Answer:

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3 years ago
In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second
Molodets [167]

Given:

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second.

To find:

The equation for the given situation if the sum of the numbers is 77.

Solution:

a. Let the first number in the set is x.

The second is 3 more than the first. So, the second number is (x+3).

The 3rd number is a square of the second. So, the third number is (x+3)^2.

Therefore, the first, second and third numbers are x,(x+3),(x+3)^2 respectively.

b. The sum of the numbers is 77.

First number + Second number + Third number = 77

c. So, the equation in terms of x is:

x+(x+3)+(x+3)^2=77

Therefore, the required equation is x+(x+3)+(x+3)^2=77.

d. On simplification, we get

x+x+3+x^2+6x+9=77                   [\because (a+b)^2=a^2+2ab+b^2]

x^2+(6x+x+x)+(3+9)=77

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Subtract 77 from both sides.

x^2+8x+12-77=77-77

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Therefore, the simplified form of the required equation is x^2+8x-65=0.

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2 years ago
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