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3 years ago

Write the point-slope equation for each line with the given slope and point. y –y1 = m(x – x1) Slope = 5 Point on line = (–1, 3)

Mathematics

1 answer:

snow_lady [41]3 years ago

4 0

Answer:

$y-3=5(x+1)$

Step-by-step explanation:

Point-Slope form is: $y-y_1=m(x-x_1)$

'm' - Slope

(x1, y1) - Point Coordinate

We are given the point of (-1,3) and the slope of 5.

Replace 'm' with 5, 'x1' with -1, and 'y1' with 3:

$y-y_1=m(x-x_1)\rightarrow\boxed{y-3=5(x+1)}$

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Write an inequality for the given statement: The sum of x and 25 is less than 75.

Kaylis [27]

That statement would be best express by " x + 25 < 75 ". Since the statement says the sum of x and 25, thus, it will be x + 25. Then it also states that the sum is less than 75, so the best expression would be " < 75".

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3 years ago

15 + 10y - 4xy - 6 6.

Verdich [7]

Answer:

Step-by-step explanation:

15+10y−4xy−66

Soustraire 66 de 15 pour obtenir −51.

−51+10y−4xy

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2 years ago

Read 2 more answers

WHOEVER GETS THIS RIGHT IN 3 MINUTES GETS THE BRAINLIEST!! Four times the sum of a number and 15 is at least 120. Let x represen

larisa [96]

Hey there!

Let's call this "number" x. We want four times the sum of this number and 15 to equal at least 120.

Therefore, we want this number times four plus fifteen to be greater than or equal to 120. We have:

$4(x+15)\geq 120$

Distribute:

$4x + 60 \geq 120$

Subtract:

$4x\geq 60$

Divide:

$x\geq 15$

Your answer is C.

Hope this helps!

7 0

3 years ago

10. (Section 4.7) John filled his gas tank and noted that the odometer read 38,320.8 miles. After the next filling, the odometer

hodyreva [135]

Find the number of miles he drove by subtracting the odometer readings:

38735.5 - 38320.8 = 414.7 miles.

Now divide the number of miles driven by the number of gallons:

414.7 / 14.5 = 28.6 miles per gallon.

6 0

3 years ago

LMN is a right-angle triangle. Angle NLM=90. PQ is parallel to LM. The area of triangle PNQ is 8cm^2. The area of triangle LPQ i

likoan [24]

Answer:

The area of LQM is $48cm^2$

Step-by-step explanation:

Given

Area of PNQ = 8

Area of LPQ = 16

See attachment for triangles

The area of PNQ is calculated as:

$Area = \frac{1}{2} * PQ * PN$

Substitute 8 for Area

$8 = \frac{1}{2} * PQ * PN$

$PQ * PN = 16$

The area of LPQ is calculated as:

$Area = \frac{1}{2} * PQ * LP$

Substitute 16 for Area

$16= \frac{1}{2} * PQ * LP$

From the attachment:

$PN + LP =LN$

Make LP the subject

$LP = LN -PN$

So:

$16= \frac{1}{2} * PQ * (LN -PN)$

We have:

$16= \frac{1}{2} * PQ * (LN -PN)$ and $PQ * PN = 16$

Equate both expressions:

$\frac{1}{2} * PQ *(LN - PN) = PQ * PN$

Divide both sides by PQ

$\frac{1}{2} (LN - PN) = PN$

Multiply both sides by 2

$LN - PN = 2PN$

$LN= 3PN$

Since PNQ is similar to LNM, the following equivalent ratios exist:

$\frac{LM}{PQ} = \frac{LN}{PN}$

Substitute $LN= 3PN$

$\frac{LM}{PQ} = \frac{3PN}{PN}$

$\frac{LM}{PQ} = 3$

$LM = 3PQ$

Area of LQM is:

$Area = \frac{1}{2} * LM * LP$

This gives:

$Area = \frac{1}{2} * 3PQ * LP$

$Area = 3 *\frac{1}{2} *PQ * LP$

Recall that:

$16= \frac{1}{2} * PQ * LP$

So:

$Area = 3 *16$

$Area = 48cm^2$

5 0

3 years ago