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Zarrin [17]
4 years ago
6

Write the point-slope equation for each line with the given slope and point. y –y1 = m(x – x1) Slope = 5 Point on line = (–1, 3)

Mathematics
1 answer:
snow_lady [41]4 years ago
4 0

Answer:

y-3=5(x+1)

Step-by-step explanation:

Point-Slope form is: y-y_1=m(x-x_1)

'm' - Slope

(x1, y1) - Point Coordinate

We are given the point of (-1,3) and the slope of 5.

Replace 'm' with 5, 'x1' with -1, and 'y1' with 3:

y-y_1=m(x-x_1)\rightarrow\boxed{y-3=5(x+1)}

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PLEASE HELP ASAP: TRIGONOMETRY
ratelena [41]

Recall that sine is the ratio of opposite over hypotenuse, so we say

sin(theta) = opposite/hypotenuse

If we have a triangle labeled as such in the diagram below, then we can use symbols to write sin(theta) = A/C

Similarly, cos(theta) = B/C since cosine is the ratio of adjacent over hypotenuse.

Then from here we use a bit of algebra to compute the left hand side of the given equation. The goal is to see if we can simplify it to 1.

\sin^2\left(\theta\right)+\cos^2\left(\theta\right)\\\\\left(\sin\left(\theta\right)\right)^2+\left(\cos\left(\theta\right)\right)^2\\\\\left(\frac{A}{C}\right)^2+\left(\frac{B}{C}\right)^2\\\\\frac{A^2}{C^2}+\frac{B^2}{C^2}\\\\\frac{A^2+B^2}{C^2}\\\\\frac{C^2}{C^2}\\\\1

So this shows that the left hand side is identically the same as the right hand side (both sides are 1), and it doesn't matter what you replace theta with. Theta can be any real number and the equation will always be true.

Note: if you're wondering how A^2+B^2 became C^2, it's because of the pythagorean theorem. So that's why this trig identity is often referred to as the pythagorean trig identity.

6 0
3 years ago
A parabola can be drawn given a focus of (2, 4)(2,4) and a directrix of x=4x=4. Write the equation of the parabola in any form.
kipiarov [429]

Answer:

The equation of the parabola is;

x = -(1/4)·(y - 4)² + 3

Step-by-step explanation:

The given focus of the parabola is f = (2, 4)

The directrix of the parabola is x = 4

The vertex form of the equation of the parabola can be expressed as follows;

x = a·(y - k)² + h

(y - k)² = 4·p·(x - h)

Where;

(h, k) = The vertex of the parabola

(h + p, k) = The focus of the parabola

x = h - p = The directrix

Therefore, k = 4

h + p = 2...(1)

h - p = 4...(2)

∴ 2·h = 6

h = 6/2 = 3

From equation (1), we have;

p = 2 - 3 = -1

p = -1

From the equation of the parabola in the form, (y - k)² = 4·p·(x - h), we have;

The equation of the parabola is (y - 4)² = 4 × (-1) ·(x - 3)

Therefore, we have;

(y - 4)² = -4·x + 12

4·x = 12 - (y - 4)²

The equation of the parabola is x = -(1/4)·(y - 4)² + 3

y² -8·y + 16 = -4·x + 12

4·x = 8·y - y² - 16 + 12 = 8·y - y² - 4

x = 2·y - y²/4 - 1 = -y²/4 + 2·y - 1

The equation of the parabola can also be written in the form

x = -y²/4 + 2·y - 1 = -0.25·y² + 2·y - 1

6 0
3 years ago
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