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zalisa [80]
3 years ago
13

What is the solution to the system of equations?

Mathematics
2 answers:
Xelga [282]3 years ago
6 0

Answer:

The solution of the given system is (5,12).

Step-by-step explanation:

Here, the given system of equations is,

3x + 2y = 39 -------(1),

5x - y = 13 ---------(2),

Equation (1) + 2 ×  Equation (2),

We get,

3x + 10 x = 39 + 26

13x = 65

⇒ x = 5

From equation (1),

3(5) + 2y = 39,

15 + 2y = 39

2y = 39 - 15

2y = 24

⇒ y = 12,

Hence, the solution of the given system is (5,12).

strojnjashka [21]3 years ago
3 0
Answer is (5,12)...
3(5)+2(12) = 39

5(5) - 12 = 13
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A line passes through (8,2) and (11,-13) write the equation of thr line in standerd form
docker41 [41]

Answer:

Step-by-step explanation:

(8,2),(11,-13)

slope(m) = (-13 - 2) / (11 - 8) = -15/3 = -5

y = mx + b

slope(m) = -5

(8,2)...x = 8 and y = 2

now we sub and find b, the y int

2 = -5(8) + b

2 = -40 + b

2 + 40 = b

42 = b

so ur equation is : y = -5x + 42...now we need it in standard form

Ax + By = C

y = -5x  42

5x + y = 42 <====

8 0
3 years ago
To solve the equation 5sin(2x)=3cosx, you should rewrite it as___.​
galina1969 [7]

Answer:

A

Step-by-step explanation:

We want to solve the equation:

5\sin(2x)=3\cos(x)

To do so, we can rewrite the equation.

Recall the double-angle for sine:

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By substitution:

5\left(2\sin(x)\cos(x)\right)=3\cos(x)

Distribute:

10\sin(x)\cos(x)=3\cos(x)

We can subtract 3cos(x) from both sides:

10\sin(x)\cos(x)-3\cos(x)=0

And factor:

\cos(x)\left(10\sin(x)-3\right)=0

Hence, our answer is A.

*It is important to note that we should not divide both sides by cos(x) to acquire 10sin(x) = 3. This is because we need to find the values of x, and one or more may result in cos(x) = 0, and we cannot divide by 0. Hence, we should subtract and then factor.

5 0
3 years ago
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What is 9 divided by 1504
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Answer:

9 ÷ 1504 = 0 R 9

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Shown above is remainder form and decimal form...

4 0
3 years ago
Triangle FGH with vertices F(6,6), G(8,8), and H(8,3): (a) Reflection: in the line x = 5 (b) Translation: (x,y)→ (x - 7, y - 9)
irakobra [83]

(a) The vertices after the reflection in the line x = 5 are F'(4,6) , G'(2,8) , H'(2,3) .

and (b) after translation , the vertices are F''(-1,-3) , G'' (1,-1) , H''(1,-6) .

In the question a triangle FGH with vertices F(6,6) , G(8,8) and H(8,3) is given

Part (a)

the rule for reflection of point (x,y) by the line x = p  is

(x,y) → (2×p - x , y)

reflection by the line x = 5 ,

we get

the vertices as

F'(2×5-6,6) = (4,6)

G'(2×5-8,8) = (2,8)

H'(2×5 - 8 ,3) = (2,3)

Part (b)

the rule of translation is given as (x,y)→ (x - 7, y - 9)

So , the vertices after translation are

F''(6-7 , 6-9) = (-1,-3)

G''(8-7,8-9) = (1,-1)

H''(8-7,3-9) = (1,-6)

Therefore , (a) The vertices after the reflection in the line x = 5 are F'(4,6)

G'(2,8) , H'(2,3) .

and (b) after translation , the vertices are F''(-1,-3) , G'' (1,-1) , H''(1,-6) .

Learn more about Translation here

brainly.com/question/3456459

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7 0
1 year ago
Tenth term of 4n-3<br><br><br><br>thank you​
RideAnS [48]

4n - 3 = 4 * 10 - 3 = 40 - 3 = 37

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