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2 years ago

Find the y-intercept of the line on the graph. Enter the correct answer.

Mathematics

2 answers:

klio [65]2 years ago

7 0

Answer:

y-intercept = -1

Step-by-step explanation:

Svetllana [295]2 years ago

6 0

The answer is y=(3/4)x-1

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Another one: (12 - 7.5) - 7

mixas84 [53]

Answer:

-2.5

Step-by-step explanation:

Plugged into calculator

5 0

2 years ago

7800 nm + 95 pm in scientific notation

azamat

$7800 nm+95pm=7800* 10^{-9} +95* 10^{-12}$
$=7800000* x^{-12} +95* 10^{-12} =7800095* 10^{-12} =7.800095* 10^{-6}$

3 0

2 years ago

The average distance between the Earth and the Moon is 384 400 km.<br> Express it in standard form.

ycow [4]

Answer:

$3.84\times10^8\ m$

Step-by-step explanation:

It is given that,

The average distance between the Earth and the Moon is 384 400 km.

We need to express in in standard form.

1 km = 1000 m

It means,

384400 km = 384400000 km

= $3.84\times10^8\ m$

Hence, the average distance between the Earth and the Moon is $3.84\times10^8\ m$ .

3 0

2 years ago

50 people took a rest before the test they predicted whether they would pass or fail 30 People predicted they would pass 26 of t

Gre4nikov [31]

37-26=11
26+4+11=41
50-41=9

5 0

2 years ago

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$

They put it in ( )

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

I'm going to go ahead and combine those fractions now:

$(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0$

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

$(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0$

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

$x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}$

$x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}$

Now subtract b/(2a) on both sides:

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Combine the fractions (they have the same denominator):

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

6 0

2 years ago