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mina [271]
3 years ago
12

Vectors and scalars (are/arenot) the same

Mathematics
2 answers:
dangina [55]3 years ago
6 0
There not the same
vectors have magnitude and direction scalars on the other hand only have magnitude
ella [17]3 years ago
4 0
They are not the same.
scalar is something that has only magnitude and no direction ,but vector has both magnitude and direction
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Find the value of a that makes m||n
Brut [27]

The value of x that makes m║n is 40°

<h3>Line of transverse on parallel lines:    </h3>

In geometry, the line that intersects two straight lines at distinct points is known as a transversal.

<h3>Corresponding angles: </h3>

The angles that are formed when two parallel lines are intersected by a third line i.e a transversal are corresponding angles.

Note:

Two corresponding angles are formed by a transversal with two parallel lines that are equal

Here we have

The angle made by the intersecting line with line m is 120°

And the angle made by the same line with line n is 3x°

Let us assume that m║n  

From above observations

The given angle are corresponding angles

=> 3x° = 120°

=> x° = 40°  

Therefore,

The value of x that makes m║n is 40°

Learn more about the Line of transverse at

brainly.com/question/11592045

#SPJ1

6 0
1 year ago
Lines l and m are parallel.<br> Use the diagram to determine the measure of ∠3.
Pavlova-9 [17]

Answer:

∠3 is 70°

Step-by-step explanation:

∠1 is 50° since it is across from another 50° angle

and then you use the equation x+25+2x+50=180 to find x

x then equals 35°

you then use the alternate interior angle theorem to say that ∠3 is 2x, or 70°

5 0
3 years ago
Please solve this law of indices​
PilotLPTM [1.2K]

4√36^-1 = 36^-1/4

36^3/4 • 36^-1/4

=36^2/4

or √36 = 6

5 0
2 years ago
Read 2 more answers
Find the domain of the function
aev [14]
Domain are those values of x for which function is defined. f(x) is not defined at x = 3. Therefore Domain is

x∈ (⁻∞, +∞) - {3}
8 0
4 years ago
Find the midpoint of the line segment with the endpoints (1, 0) and (2, -10).
Mariulka [41]

Answer:

\bigl(\frac{3}{2},-5\bigr)

or in decimal form

(1.5,-5)

Step-by-step explanation:

The midpoint of the line with endpoints (x_1,y_1) and (x_2,y_2) is \bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr). just take the average between the points

so given the points (1,0) and (2,-10)

x_1=1

y_1=0

x_2=2

y_2=-10

the midpoint is found as follows:

\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)

\bigl(\frac{1+2}{2},\frac{0-10}{2}\bigr)

\bigl(\frac{3}{2},\frac{-10}{2}\bigr)

\bigl(\frac{3}{2},-5\bigr)

or in decimal form

(1.5,-5)

7 0
4 years ago
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