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Sedbober [7]
3 years ago
11

Today there are a total of six toll-free area codes: 800, 844, 855, 866, 877, and 888. Assume that all seven digits for the rest

of a number are
possible, and determine how many toll-free numbers there are now.
Mathematics
1 answer:
Ludmilka [50]3 years ago
4 0

Answer:

6 \times 10^{7}

Step-by-step explanation:

Total number of toll-free area codes = 6

A complete number will be of the form:

800-abc-defg

Where abcdefg can be any 7 numbers from 0 to 9. This holds true for all the 6 area codes.

Finding the possible toll free numbers for one area code and multiplying that by 6 will give use the total number of toll free numbers for all 6 area codes.

Considering: 800-abc-defg

The first number "a" can take any digit from 0 to 9. So there are 10 possibilities for this place. Similarly, the second number can take any digit from 0 to 9, so there are 10 possibilities for this place as well and same goes for all the 7 numbers.

Since, there are 10 possibilities for each of the 7 places, according to the fundamental principle of counting, the total possible toll free numbers for one area code would be:

Possible toll free numbers for 1 area code = 10 x 10 x 10 x 10 x 10 x 10 x 10 = 10^{7}

Since, there are 6 toll-free are codes in total, the total number of toll-free numbers for all 6 area codes = 6 \times 10^{7}

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Whats the diffrence of 2 2/3 - 1 2/5 write answer in simplest form
Fofino [41]
2 \frac{2}{3}-1 \frac{2}{5}=2 \frac{2 \times 5}{3 \times 5}-1 \frac{2 \times 3}{5 \times 3}=2 \frac{10}{15}-1 \frac{6}{15}=\boxed{1\frac{4}{15}}
3 0
3 years ago
Read 2 more answers
SOMEONE HELP PLEASE! ASAP!
Luba_88 [7]
When two lines intersect, the angles across from the intersection (the "X") are congruent (equal), and referred to as "vertical angles."
So by the rule of vertical angles are congruent, we can set them equal:
{x}^{2}  - 6x = 1\div2 \: x + 42 \\  {x}^{2}  - 6x - 1 \div 2 \: x = 42 \\  {x}^{2}  - 6.5x = 42
{x}^{2}  - 6.5x - 42 = 0 \\ multiply \: both\: sides \: by \: 2 \: to \: get \\ rid \: of \: the \: decimal \\ 2({x}^{2}  - 6.5x - 42) = 2(0)
2 {x}^{2}  - 13x - 84 = 0
to factor we need the factors of 84:
1×84, 2×42, 3×28, 4×21, 6×14
Now we need one of those factors ×2 ( from the x^2 term) minus the other factor to equal 13 (the middle term)
it turns out that if we use 4×21: 4×2 = 8
and 21-8 = 13. Woohoo! we got it
So now we have:
2 {x}^{2}  - 13x - 84 = 0 \\ (2x - 21)(x + 4) = 0
Now set each factor = 0
1) 2x - 21 = 0 and 2) x + 4 = 0
1) 2x - 21 = 0, 2x = 21, x = 21/2 = 10.5
2) x + 4 = 0, x = -4

Now we plug in each answer to check:
1) x = 10.5
{x}^{2}  - 6x =  {(10.5)}^{2}  - 6(10.5) \\  = 110.25 - 63 = 47.25
1/2x + 42 = 1/2(10.5) + 42 = 5.25 + 42 = 47.25
47.25 = 47.25
BAM SO IT LOOKS LIKE THAT'S IT!!
But let's check 2) first:
2) x = -4
{( - 4)}^{2}  - 6( - 4) = 16 + 24 = 40
1/2x + 42 = 1/2(-4) + 42 = -2 + 42 = 40
40 = 40, so both work!!
But it asks for m<1, and <1 is supplementary because it lies on same line, meaning the sum of both = 189
Therefore m<1 = 180 - 47.25 = 132.75°
OR m<1 = 180 - 40 = 140°


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3 years ago
If L
BabaBlast [244]
Pythagorean's theorem says the hypotenuse of a triangle is A^2+B^2=C^2 in this case I'll put the L,W, and D so it's easy to understand. L^2+W^2=D^2 is the exact same formula as above and is how we will solve this. (30^2)+(10^2)=1000 then we take the square root since 1000=D^2, and we get 36.62 as D.
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3 years ago
What is the solution to the system of equations?
elixir [45]

Answer:

No solution

Step-by-step explanation:

-3x-4y-3z=-7\\2x-6y+2z=3\\5x-2y+5z=9\\\\

Lets consider the equation 2.

Here we multiply the LHS and RHS with (-1).

-3x-4y-3z=-7\\-(2x-6y+2z)=-3\\5x-2y+5z=9\\\\

Hence,

-3x-4y-3z=-7\\-2x+6y-2z=-3\\5x-2y+5z=9\\\\

When we add the equations we get,

0x+0y+0z=-10+9\\Hence,\\0=-1

As 0 doesn't equal to -1, answer is d) No solution

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