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vichka [17]
2 years ago
15

50 POINTS !!

Mathematics
1 answer:
vitfil [10]2 years ago
4 0

Answer:

Step-by-step explanation:

Hope this helps u!!

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Help me<br><br>6 = 1/5 (4y + 10)​
gregori [183]

Step-by-step explanation:

open the bracket

6={(1/5×4y) + 1/5×10}

6=4/5y+2

6-2=4/5y

4=4/5y

divide both sides by 4/5

y=1/5

4 0
3 years ago
Read 2 more answers
Learn with an example<br> Find the perimeter. Simplify your answer.<br> y-6<br> y-5<br> y-5<br> y-6
koban [17]

Answer:

P = 22

Step-by-step explanation:

P= l(2) + w(2)

5(2) + 6(2)

10 + `12

22

6 0
3 years ago
Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul
IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: P(k) = \frac{\lambda^ke^{-k}}{k!} where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and \lambda = 7 into the formula:

P(k=7) = \frac{7^7e^{-7}}{7!}

P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

P(k\leq2) = P(k=0)+P(k=1)+P(k=2)

P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}

P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}

P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%

4 0
3 years ago
John wants to invite around 78,000 college students to a tournament. Which of the following sets of college student populations
Ad libitum [116K]

Answer:

a

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
In a history class, students take a weekly multiple choice quiz consisting of 6 questions, each with 4 possible answers. if a st
Mademuasel [1]
There are 24 possible answers, 6 are correct answers and 18 are incorrect answers. By use of the hypergeometric distribution the probabilities of each possible number of randomly selected correct answers can be found, as follows:
P(0) = 0.1379, P(1) = 0.3819, P(2) = 0.341, P(3) = 0.1213, P(4) = 0.017, P(5) = 0.0008, P(6) = 0.000007.
The expected or mean number of correct answers is found from:
E(X)=0\times0.1379+1\times0.3819+2\times0.341+3\times0.1213+4\times0.017+5\times0.0008+6\times0.000007=1.4998
The answer is: 1.4998

8 0
3 years ago
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