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wlad13 [49]
3 years ago
12

Solve for x: 2(x + 3)2 − 4 = 0

Mathematics
2 answers:
kolbaska11 [484]3 years ago
8 0

Answer:

Option D is correct

Step-by-step explanation:

I took the test

asambeis [7]3 years ago
6 0

Answer:

Option D) x = −4.41, −1.59

Step-by-step explanation:

We are given the following expression in the question:

2(x + 3)^2 - 4 = 0

Solving the above expression, we get:

2(x + 3)^2 - 4 = 0\\2(x^2+9+6x)-4=0\\\text{Identity: }(a+b)^2 = a^2 + b^2 + 2ab\\2x^2+18+12x-4=0\\2x^2+12x+14=0\\\text{Using the quadratic formula:}\\ax^2 + bx +_ c = 0\\\\x = \displaystyle\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\text{Puting a = 2, b = 12, c = 14}\\\\x = \displaystyle\frac{-12\pm \sqrt{(12)^2-4(2)(14)}}{2(2)}\\\\x = \frac{-12 \pm 5.65}{4}\\\\x = \frac{-12 + 5.65}{4}, \frac{-12-5.65}{4} = -1.5875, -4.4125 \approx -1.59, -4.14

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Resultado de esta cuenta Explicada cuenta completa:<br><br>(6+3)²=​
Mumz [18]

81 is the correct answer

hope it helps you have a good day

7 0
3 years ago
124 ounces decreased by 67%
slavikrds [6]
40.92 ounces.
You can find it by multiplying 124 by 0.33
8 0
3 years ago
Read 2 more answers
Solve for C:<br> Spam: deiodhwidweiudjegydjwe
Maksim231197 [3]

Answer:

C=\frac{5F-160}{9}

Step-by-step explanation:

Let's solve for C.

F=\frac{9C}{5}

Step 1: Flip the equation.

\frac{9}{5} C+32=F

Step 2: Add -32 to both sides.

\frac{9}{5} C+32+-32=F+-32

\frac{9}{5}C=F-32

Step 3: Divide both sides by \frac{9}{5}.

\frac{\frac{9}{5}C}{\frac {9} {5}}=\frac{F-32}{\frac{9}{5} }

C=\frac{5F-160}{9}

Answer:

C=\frac{F-160}{9}

8 0
3 years ago
Please answer this one, I’m in math grade 9 having online classes i need your help for this one. Asap thanksss
ICE Princess25 [194]

Answer:

1) b

2)d

3)a

Step-by-step explanation:

1) count the number of different betwwen 2 cycles

2) take 5/160 time 8

3) take 12/9.6 then times 6.4

8 0
3 years ago
The perimeter of XYZ is ___ units.
In-s [12.5K]

Look at the picture.

ZY = 5+3=8

For XY and ZX use the Pythagorean theorem.

XY^2=3^2+4^2\\\\XY^2=9+16\\\\XY^2=25\to XY=\sqrt{25}\\\\XY=5

ZX^2=5^2+4^2\\\\ZX^2=25+16\\\\ZX^2=41\to ZX=\sqrt{41}

The perimetero fo XYZ:

P_{\triangle XYZ}=8+5+\sqrt{41}=\boxed{13+\sqrt{41}}

7 0
3 years ago
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