The probability of one arrives within the next 10 minutes
when he already been waiting for one jour for a taxi is,
P (X > 70 | X > 60) = P (X > 10) = 1 – P (X ≤ 10)
= 1 – {1 – e ^ -((1 / 10) 10)} = e ^ -1
= 0.3679
The probability of one arrives within the next 10 minutes
when he already been waiting for one hour for a taxi is 0.3679
Step-by-step explanation:
35 × 10^-3 × 102 × 10 ^-2
35×102 ×10^-3-2
3570× 10^-5
3.57×10^-2
Answer:
Step-by-step explanation:
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