small frames ($8): s
large frames ($15): L
Cost: 8s + 15L = 239 ⇒ 1(8s + 15L = 239) ⇒ 8s + 15L = 239
Quantity: s + L = 22 ⇒ -8( s + L = 22) ⇒ <u> -8s -8 L = -176 </u>
7L = 63
L = 9
Quantity: s + L = 22 ⇒ s + (9) = 22 ⇒ s = 13
Answer: 13 small frames, 9 Large frames
Cd is equal to this: first calculate AB by sin30 which is radical 3 then by sin45 you know bc is radical 3 too then by fisaghures ( idk what you call it)
calculate bd at the end you just gotta do this: bd-bc
There are 24 half miles in 12 miles.
If other tickmarks are labeled, then you could do some detective work (of sorts) to figure out the unlabeled tickmarks.
For example, let's say we had a number line with 1,2,3,... and let's say that 7 was covered up or erased or smudged. So we have 1,2,3,4,5,6,__,8,9. We could then easily determine that 7 must go in that blank spot. This is just one example of course.
Another example could be that if we had a tickmark right in the middle of two whole numbers, say 0 and 1. This unlabeled tickmark would most likely be 1/2 = 0.5 as its at the halfway point between 0 and 1.
Answer:
y+2= -1/5(x+1)
Step-by-step explanation:
if lines are perpendicular their slopes are negative reciprocal
y=mx+b where m is the slope
y=5x-10 has the slope 5 so a perpendicular line will have slope -1/5
equation point slope form
(y-y1) = m(x-x1) where m is slope, and (x1,y1) any point that belongs to the line
y+2= -1/5(x+1)
