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ira [324]
3 years ago
12

Fake Question: Should Sekkrit be a moderator? (answer if you can) Real Question: Solve for x.

x%5E2%2B3x%3D-2" id="TexFormula1" title="x^2+3x=-2" alt="x^2+3x=-2" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
sweet [91]3 years ago
7 0

Answer:

x = -2       <u><em>OR</em></u>      x = -1

Step-by-step explanation:

=> x^2+3x = -2

Adding 2 to both sides

=> x^2+3x+2 = 0

Using mid-term break formula

=> x^2+x+2x+2 = 0

=> x(x+1)+2(x+1) = 0

=> (x+2)(x+1) = 0

Either:

x+2 = 0    <u><em>OR</em></u>     x+1 = 0

x = -2       <u><em>OR</em></u>      x = -1

P.S. Ummmm maybe...... Because he usually reports absurd answers! So, Won't it be better that he could directly delete it. And one more thing! He's Online 24/7!!!!!

monitta3 years ago
5 0

Answer:

x = -2 , -1

Step-by-step explanation:

Set the equation equal to 0. Add 2 to both sides:

x² + 3x = -2

x² + 3x (+2) = - 2 (+2)

x² + 3x + 2 = 0

Simplify. Find factors of x²  and 2 that will give 3x when combined:

x²  + 3x + 2 = 0

x               2

x               1

(x + 2)(x + 1) = 0

Set each parenthesis equal to 0. Isolate the variable, x. Note that what you do to one side of the equation, you do to the other.

(x + 2) = 0

x + 2 (-2) = 0 (-2)

x = 0 - 2

x = -2

(x + 1) = 0

x + 1 (-1) = 0 (-1)

x = 0 - 1

x = -1

x = -2 , -1

~

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Answer:

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Step-by-step explanation:

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now, we can plug these values into formula

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0.15=0.1

we can see that left side is not equal to right side

so, this is FALSE


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