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3 years ago

HEY GUYS SO I BEEN GIVING FREE COINS FOREVERYBODY YOU GET THIS THANK ME AND PROFILE

Mathematics

2 answers:

mylen [45]3 years ago

5 0

Answer:

thanskkkkss broo!!

Step-by-step explanation:

topjm [15]3 years ago

3 0

Answer:cool

Step-by-step explanation:

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Find the largest whole number which is a factor of both 42 and 98

LuckyWell [14K]

Answer:

Step-by-step explanation:

hope this helps

5 0

2 years ago

In triangle ABC, m<A = 30° and m<B = 50°. What is the measure of Angle C?<br><br>

Nataliya [291]

Answer:

100°

Step-by-step explanation:

The sum of the angles in a triangle is 180°

180°-30°-50°=100°

8 0

2 years ago

If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.

nydimaria [60]

Answer:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

Step-by-step explanation:

Given

$\cos(\theta) = -\frac{2}{3}$

$\theta \to$ Quadrant III

Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

We have:

$\cos(\theta) = -\frac{2}{3}$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$\sin^2(\theta) + (-\frac{2}{3})^2 = 1$

$\sin^2(\theta) + (\frac{4}{9}) = 1$

Collect like terms

$\sin^2(\theta) = 1 - \frac{4}{9}$

Take LCM and solve

$\sin^2(\theta) = \frac{9 -4}{9}$

$\sin^2(\theta) = \frac{5}{9}$

Take the square roots of both sides

$\sin(\theta) = \±\frac{\sqrt 5}{3}$

Sin is negative in quadrant III. So:

$\sin(\theta) = -\frac{\sqrt 5}{3}$

Calculate $\csc(\theta)$

$\csc(\theta) = \frac{1}{\sin(\theta)}$

We have: $\sin(\theta) = -\frac{\sqrt 5}{3}$

So:

$\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}$

$\csc(\theta) = \frac{-3}{\sqrt 5}$

Rationalize

$\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}$

$\csc(\theta) = \frac{-3\sqrt 5}{5}$

So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)$

Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

6 0

3 years ago

No pinks plz just tell me the answer

uranmaximum [27]

Answer:

none of the equations are true, B!

Step-by-step explanation:

8 isn't equal to 7

9 isn't equal to 8

and 125 isn't equal to 15 :D

6 0

2 years ago

Read 2 more answers

Can someone help me with this equation

Alexxandr [17]

Answer:

D) y=250-6x

Step-by-step explanation:

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3 years ago