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Gnoma [55]
3 years ago
7

What is the measure of KPN? A. 35° B. 50° C. 60° D.65° E. 70°

Mathematics
1 answer:
luda_lava [24]3 years ago
3 0

Answer:

Option (B)

Step-by-step explanation:

From the picture attached,

NL and KM are the two lines intersecting at a point P.

Therefore, ∠KPN ≅ LPM [Vertical angles]

In ΔPLM,

m∠LPM + m∠PML + m∠PLM = 180° [Property of a triangle]

m∠LPM + 70° + 60° = 180°

m∠LPM + 130° = 180°

m∠LPM = 180° - 130°

m∠LPM = 50°

Therefore, m∠KPN = 50° [vertical angles]

Option (B) will be the correct option.

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Write each number<br><br> 1. 1,000 more than 3,872
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The value for a number that is 1000 more than 3,872 will be 4,872

In the given question, it is stated that we have to find out the value of the expression given. The expression states that we have to find out a number that is 1000 more than 3872.

This can easily be done. To find out the value for a number that is 1000 greater than 3872, we just need to add the value to the number i.e. we need to add 1000 to 3872. Let the new number be 'x'.

So, by solving this condition, we get

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1 year ago
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3 0
3 years ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
The scale of a map is 6 km = 4 mi. What is the length on the map if the actual is 40.1<br> miles.
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Answer:

60.15 km

Step-by-step explanation:

If 6 km on the map represents 4 mi on land, then we'd get the answer by using the relation

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That is the length we're looking for

8 0
3 years ago
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