
The lifeguard of the beach resort is on his post which is 4 m high. A boy in the pool is 9 meters away from him. Find the angle of depression from the lifeguard to the boy.






Therefore the angle of depression from the lifeguard to the boy is 24°.
Answer:
Step-by-step explanation:
tan Θ + tan 2Θ + √3 tan Θ tan 2Θ = √3
tan Θ + tan 2Θ = √3 - √3 tan Θ tan 2Θ
tan Θ + tan 2Θ = √3 ( 1 - tan Θ tan 2Θ)
(tan Θ + tan 2Θ) / (1 - tanΘ tan 2Θ) = √3
tan(Θ + 2Θ) = √3
tan 3Θ = tan (
) we know tan Θ = tan α; Θ = nΠ + α, n belongs to z
3Θ = nΠ + Π/3
Θ = nπ/3 + Π/9 for all n in Z
The answer is C you dived the circumference by 2 and use the formula for the area of a circle which is A = π × r^2