Question

Find the perimeter & area of the rectangle

Answer 1

Answer:

Perimeter = $34\sqrt{2}$ feet

Area = 60 feet²

Step-by-step explanation:

Let us revise the rules of perimeter and area of a rectangle

• Perimeter = 2(Length + width)

• Area = Length × Width

→ From the given figure

∵ The length = $\sqrt{8}$ feet

∵ The width = 5$\sqrt{18}$ feet

→ Simplify the roots

∵ $\sqrt{8}=\sqrt{(2)(2)(2)}$

∴ $\sqrt{8}=2\sqrt{2}$

∴ The length = $2\sqrt{2}$ feet

∵ $5\sqrt{18}=5\sqrt{(3)(3)(2)}$

∴ $5\sqrt{18}=5(3)\sqrt{2}=15\sqrt{2}$

∴ The width = $15\sqrt{2}$ feet

→ Perimeter = 2(Length + width)

∵ Perimeter = $2[2\sqrt{2}+15\sqrt{2}]$

∴ Perimeter = $2[17\sqrt{2}]$

∴ Perimeter = $34\sqrt{2}$ feet

→ Area = Length × Width

∵ Area = $2\sqrt{2}$ × $15\sqrt{2}$

∴ Area = $(2)(15)(\sqrt{2})(\sqrt{2})=(30)(2)=60$

∴ Area = 60 feet²