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Sladkaya [172]
3 years ago
11

Find the perimeter & area of the rectangle

Mathematics
1 answer:
NikAS [45]3 years ago
8 0

Answer:

Perimeter = 34\sqrt{2} feet

Area = 60 feet²

Step-by-step explanation:

Let us revise the rules of perimeter and area of a rectangle

  • Perimeter = 2(Length + width)
  • Area = Length × Width

→ From the given figure

∵ The length = \sqrt{8} feet

∵ The width = 5\sqrt{18} feet

→ Simplify the roots

∵ \sqrt{8}=\sqrt{(2)(2)(2)}

∴ \sqrt{8}=2\sqrt{2}

∴ The length = 2\sqrt{2} feet

∵ 5\sqrt{18}=5\sqrt{(3)(3)(2)}

∴ 5\sqrt{18}=5(3)\sqrt{2}=15\sqrt{2}

∴ The width = 15\sqrt{2} feet

→ Perimeter = 2(Length + width)

∵ Perimeter = 2[2\sqrt{2}+15\sqrt{2}]

∴ Perimeter = 2[17\sqrt{2}]

∴ Perimeter = 34\sqrt{2} feet

→ Area = Length × Width

∵ Area = 2\sqrt{2} × 15\sqrt{2}

∴ Area = (2)(15)(\sqrt{2})(\sqrt{2})=(30)(2)=60

∴ Area = 60 feet²

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