X + 8 = 10 solve by subtraction

Nadya [2.5K]

74.5 x 0 = 0 belongs to the multiplication property of zero.
Because this property has a rule that any number multiplied by zero, the answer is zero.
It will not matter how big or small the number is, if it will be multiplied by zero, the answer will always be zero.
Another example:
=> 1000 x 0 = 0
=> 1524 x 0 = 0
=> .25 x 0 = 0
Notice, that even decimal numbers multiplied by zero is still zero.

7 0

3 years ago

Helppppppppppppppppppppppppppppp

mafiozo [28]

Answer:

1.) x=3 2.)n= -1/4 3.) h=7

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Find the value of the expression 0.5^10/0.5^7

SIZIF [17.4K]

Answer:

The solution is:

$\frac{0.5^{10}}{0.5^7}=0.125$

Step-by-step explanation:

Given the expression

$0.5^{10}\div 0.5^7$

Solving

$\frac{0.5^{10}}{0.5^7}$

$\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}$

so

$\frac{0.5^{10}}{0.5^7}=0.5^{10-7}$

$\mathrm{Subtract\:the\:numbers:}\:10-7=3$

$=0.5^3$

$=0.125$ ∵ $0.5^3=0.125$

Therefore, the solution is:

$\frac{0.5^{10}}{0.5^7}=0.125$

7 0

3 years ago

A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. (a) What must be true

valentina_108 [34]

Answer:

(a) The distribution of the sample mean ( $\bar x$ ) is N (68, 4.74²).

(b) The value of $P(\bar X$ is 0.7642.

(c) The value of $P(\bar X\geq 69.1)$ is 0.3670.

Step-by-step explanation:

A random sample of size n = 10 is selected from a population.

Let the population be made up of the random variable X.

The mean and standard deviation of X are:

$\mu=68\\\sigma=15$

(a)

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. n = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

$\mu_{\bar x}=\mu=68$