number of pockets inside jacket
Larry needs
to score
33 points in the last game to have an average of 25 PPG.
To find the answer, we can solve the equation:

<em />(where <em>p</em> is how many points he needs to score in the last game)
To find the mean of a group of numbers, you add them all up and divide the total by the number of numbers there are. Since Larry averaged 23 PPG in 4 games, we can multiply 23 by 4 to get the total of the first 4 games from the data. Then, we find <em>p</em>, which we will add to get our final total. Then, you divide by the 5 games.




First, I simplified 4 x 23 to get 92. Then, I multiplied each side by 5 to get rid of the denominator. Finally, I subtracted 92 from each side to isolate <em>p</em>, and found that <em>p</em> = 33.
You can’t really answer this without showing us the the answer you got from item 6
Answer:
Step-by-step explanation:
<u>Given the scale factor:</u>
Since the cylinders are similar, the other dimensions should have same scale factor of 1/3.
<u>The volumes are:</u>
<u>Ratio of volumes is the cube of the scale factor, as the volume is the product of 3 dimensions:</u>
- v/x = k³
- 67/x = (1/3)³
- x = 67*27
- x = 1809 cm³
9514 1404 393
Answer:
[[274][895][136]]
Step-by-step explanation:
Starting with the middle row, we need a product of two single-digit numbers that is between 53-1 = 52 and 53-9 = 44. Possible products are 5×9=45 and 6×8=48. This means the number in the middle position in the left column must be 8 or 5.
The middle number in the left column cannot be 5, because we must be able to get -5 by subtracting that number from a sum that is at least 3 = 1+2. So, the middle number in the left column is 8, the other two numbers in that column are 1 and 2, and the other two numbers in the middle row are 5 and 9.
There is no product of single-digit numbers that is 30-1 = 29, so the upper left number must be 2, and the bottom left number must be 1. The other two numbers on the top row must be 4 and 7, so that row's equation is 2+4×7=30.
The only remaining digits are 3 and 6. In order to have -3 on the bottom row, the equation there must be 1×3-6 = -3. Then the middle digit must be divisible by 3, so must be 9.
Our solution is ...
row 1: 2 + 7 × 4 = 30
row 2: 8 + 9 × 5 = 53
row 3: 1 × 3 - 6 = -3
And that makes the column equations be ...
col 1: 2 - 8 + 1 = -5
col 2: 7 + 9 / 3 = 10
col 3: 4 × 5 - 6 = 14