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4 years ago

13

How many pounds of salted nuts selling for $1.60 per pound should be mixed with 6 pounds of salted nuts selling for $2.80 per po

und to obtain a mixture selling for $2.32 per pound? HOW DO U DO THIS IM SO STRESSED!

2 answers:

aev [14]4 years ago

7 0

The answer would be 16.80

Scorpion4ik [409]4 years ago

6 0

The answer you are looking for is 16.80 hope this helps

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If sin A = 3/8, find the value of cosec A - sec A.

alexira [117]

Answer:

$\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

Step by step explanation:

$\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies 1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\$

$\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}$

$\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

6 0

2 years ago

For each $n \in \mathbb{N}$, let $A_n = [n] \times [n]$. Define $B = \bigcup_{n \in \mathbb{N}} A_n$. Does $B = \mathbb{N} \time

andre [41]

Answer:

No, it is not.

Step-by-step explanation:

The set $C = \mathbb{N} \times \mathbb{N}$ contains every ordered pair of Natural numbers, while B only contains those pairs in which both values in each entry are the same. Therefore, C is a bigger set than B, but B is not equal to C because for example C contains $[1] \times [2]$ and B doesnt because 1 is not equal to 2.

4 0

3 years ago

Just number 14. Nothing other unless u want to

Shkiper50 [21]

Answer: 4 parfaits.

Step-by-step explanation: 1/2 divided by 1/8. when you divide you flip the second fraction and multiply it so now it's 1/2 x 8/1 which is 8/2 and then is turned into 4 so 4 parfaits

Hope this helps im really good at fractions if you need anything else lol :')

6 0

3 years ago

(9-a+5a)/c (a=6,c=9)

SIZIF [17.4K]

$\frac{9-a+5a}{c} = \frac{9-(6)+5(6)}{(9)}= \frac{3+30}{9} = \frac{33}{9} = \frac{11}{3}$

7 0

3 years ago

Explain I don’t understand

Serggg [28]

So just divide 100 by 25 which equals 4 then divide 120 by 30 which also equals to 4 and if the rest equal 4 then its proportional (1)
And then same for 2 and 3 just divided the bottom by the top and if they all get the same answer they are proportion and if one is not the same then it’s not

For the grids if the dots are line diagonally straight and it starts at the 0 then it’s proportional if not then it’s not

Hope this helps :)

7 0

3 years ago