Answer:
C. (-3,11)
Step-by-step explanation:
Tp is (-3,6) implies the quadratic could have been
f(x) = (x+3)²+6
(2/3)f(x) = (2/3)[(x+3)²+6]
= (2/3)(x+3)²+4
(2/3)f(x)+3 = (2/3)(x+3)²+4+3
= (2/3)(x+3)²+7
Tp at (-3,7)
Alternately,
No change in domain so x remains-3
(2/3)f(x) changes y from 6 to 4 (6×2/3)
+3 increases the y by 3
i.e 4+3 = 7
So, (-3,7)
Answer:
6
Step-by-step explanation:
Call pentagon p, circle c and triangle t
We have 2c + 2p = 2p + 2t + c
p = 5, t = 3 so
2c + 2(5) = 2(5) + 2(3) + c
2c + 10 = 10 + 6 + c
2c = 6 + c
c = 6
Let’s remember the most basic thing in percentages, the equation.
Percent x Whole = Part.
We know the whole, and the part, but we are trying to find the percent, so we have to divide the two, first turn your whole and part into a decimal.
Percent x 0.4 = 0.18, so we divide 0.18 by 0.4
0.18/0.4 = 0.45
0.45 = 45%
Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The probability of a bulb lasting for at most 569 hours is the <u>p-value of Z when X = 569</u>, hence:


Z = 1.16
Z = 1.16 has a p-value of 0.877.
0.877 = 87.7% probability of a bulb lasting for at most 569 hours.
More can be learned about the normal distribution at brainly.com/question/24663213
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4 + 15 - 10, because that would make 9
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