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Stels [109]
3 years ago
7

Becky is competing in a 8-mi road race. She runs at a constant speed of 6 mi/h write an equation in slope intercept form to repr

esent the distance becky has left to run.
Mathematics
1 answer:
enot [183]3 years ago
6 0

Answer:

y=-6x+8

Step-by-step explanation:

8 is the miles she has she runs 6 miles so she has 2 miles left that's why when we put it in slope intercept forms it's going to be

y=-6x+8

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If figure f is rotated 180 degrees and dilated by a factor of 1/2 which new figure could be produced
andrey2020 [161]
A right angle maybe?
6 0
2 years ago
If the square root of 61 is the longest side length in the triangle and the shorter sides are x and x+1, find the value of x tha
Tju [1.3M]

Answer:

  x = 5

Step-by-step explanation:

You want to find x such that ...

  x^2 +(x +1)^2 = 61

  2x^2 +2x -60 = 0 . . . . . simplify, subtract 61

  x^2 +x -30 = 0 . . . . . . . divide by 2

  (x +6)(x -5) = 0 . . . . . . . . factor; solutions will make the factors be zero.

The relevant solution is x = 5.

5 0
2 years ago
What is the slant height for the given pyramid to the nearest whole unit?
Blababa [14]
Im assuming the height is dropped so that it is the halfway point. this would then make the base 5cm, with a height of 12cm. if that is the case then the answer should be 13
4 0
3 years ago
3x - y = 7 6x - y = 10 When solving this system of equations by elimination, which could be the resulting equation when a variab
max2010maxim [7]
It depends on which variable is eliminated.

If you multiply the second equation by -1 and eliminate the y:
3x - y = 7
-6x + y = -10
-3x = -3 or x = 1
 
If you multiply the first equation by -2 and eliminate the x:
-6x + 2y = -14
6x - y = 10
y = -4


6 0
2 years ago
Write and equation for the shift of the parent graph y=1/x
SashulF [63]
You can think of this equation as \bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}

and thus apply the transformations to it as such

\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

1)  D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7
7 0
2 years ago
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