The value of f(a)=4-2a+6
, f(a+h) is 
, [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6
.
Given a function f(x)=4-2x+6.
We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.
Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.
f(a)=4-2a+6 (By just putting x=a).
f(a+h)==
=4-2a-2h+6(
)
=4-2a-2h+6
=
[f(a+h)-f(a)]/h=[-(4-2a+6 )]/h
=
=
=6h+12a-2.
Hence the value of function f(a)=4-2a+6, f(a+h) is , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6.
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That's definitely an example of exponential decay, since the base (1/2) (also called the "common ratio") is greater than 0 but less than 1.
Answer: the answer is 3(7+3)
Step-by-step explanation: since 7+3 is in paranthases you add them first to get 10 and you multiply it by the 3 to get 30. We know its correct because 21+9=30.
Answer:
nine hours
Step-by-step explanation:
48 divided by 6 is 8 and 8 times 9 is 72
The magnification is 0.54
Given,
The distance between object and concave lens, u = -21 cm
Focal length of the concave lens, f = -25 cm
Let m be the magnification.
m = v/u
Here v is the position of image.
We have to find v first.
By using lens equation we can determine v.
That is,
1/f = 1/v – 1/u
So,
- (1/25) = 1/v – (-1/21)
- (1/25) = 1/v + 1/21
1/v = - (1/25) – 1/21
1/v = (-25 – 21) / (21 x 25)
1/v = - (46/525)
Therefore v = - (525/46)
v = -11.41 cm
Now we have to find magnification, m.
m = v/u
= (-11.41) / (-21)
= 0.54
Here magnification is 0.54
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