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Sonbull [250]
3 years ago
5

What fraction of an hour is 120 seconds?

Mathematics
2 answers:
sattari [20]3 years ago
6 0
There are 3600 seconds in one hour. 
120 seconds is 2 minutes
therefore, the fraction is \frac{2}{60}
Elza [17]3 years ago
3 0
The fraction of an hour 120 seconds is 1/30.

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What is the GCF of 35 and 49??
Vlada [557]

Answer: 7

Step-by-step explanation: 7x7=49 and 7x5=35

3 0
3 years ago
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Qual será o tempo de queda se uma pedra cair de uma altura de 19,9<br> metros?
tensa zangetsu [6.8K]
<span><span><span><span>g<span>t2</span></span>2</span>=2g</span><span><span><span>g<span>t2</span></span>2</span>=2g</span></span><span> or 19.9m.</span>
4 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
Oksana_A [137]

Answer:

n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}

Step-by-step explanation:

Lets divide it in cases, then sum everything

Case (1): All 5 numbers are different

 In this case, the problem is reduced to count the number of subsets of cardinality 5 from a set of cardinality n. The order doesnt matter because once we have two different sets, we can order them descendently, and we obtain two different 5-tuples in decreasing order.

The total cardinality of this case therefore is the Combinatorial number of n with 5, in other words, the total amount of possibilities to pick 5 elements from a set of n.

{n \choose 5 } = \frac{n!}{5!(n-5)!}

Case (2): 4 numbers are different

We start this case similarly to the previous one, we count how many subsets of 4 elements we can form from a set of n elements. The answer is the combinatorial number of n with 4 {n \choose 4} .

We still have to localize the other element, that forcibly, is one of the four chosen. Therefore, the total amount of possibilities for this case is multiplied by those 4 options.

The total cardinality of this case is 4 * {n \choose 4} .

Case (3): 3 numbers are different

As we did before, we pick 3 elements from a set of n. The amount of possibilities is {n \choose 3} .

Then, we need to define the other 2 numbers. They can be the same number, in which case we have 3 possibilities, or they can be 2 different ones, in which case we have {3 \choose 2 } = 3  possibilities. Therefore, we have a total of 6 possibilities to define the other 2 numbers. That multiplies by 6 the total of cases for this part, giving a total of 6 * {n \choose 3}

Case (4): 2 numbers are different

We pick 2 numbers from a set of n, with a total of {n \choose 2}  possibilities. We have 4 options to define the other 3 numbers, they can all three of them be equal to the biggest number, there can be 2 equal to the biggest number and 1 to the smallest one, there can be 1 equal to the biggest number and 2 to the smallest one, and they can all three of them be equal to the smallest number.

The total amount of possibilities for this case is

4 * {n \choose 2}

Case (5): All numbers are the same

This is easy, he have as many possibilities as numbers the set has. In other words, n

Conclussion

By summing over all 5 cases, the total amount of possibilities to form 5-tuples of integers from 1 through n is

n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}

I hope that works for you!

4 0
3 years ago
Tape diagram to subtract 33-19
Tpy6a [65]
Well 33 - 19 = 14 and what do u mean tape diagram?
3 0
3 years ago
Find the variance of the following data. Round your answer to one decimal place. x 1 2 3 4 5 P(X=x) 0.3 0.2 0.2 0.1 0.2
Reptile [31]

The variance of a distribution is the square of the standard deviation

The variance of the data is 2.2

<h3>How to calculate the variance</h3>

Start by calculating the expected value using:

E(x) = \sum x* P(x)

So, we have:

E(x) = 1 * 0.3 + 2* 0.2 +3 * 0.2 + 4 * 0.1 + 5 * 0.2

This gives

E(x) = 2.7

Next, calculate E(x^2) using:

E(x^2) = \sum x^2* P(x)

So, we have:

E(x^2) = 1^2 * 0.3 + 2^2* 0.2 +3^2 * 0.2 + 4^2 * 0.1 + 5^2 * 0.2

E(x^2) = 9.5

The variance is then calculated as:

Var(x) = E(x^2) - (E(x))^2

So, we have:

Var(x) = 9.5 - 2.7^2

Var(x) = 2.21

Approximate

Var(x) = 2.2

Hence, the variance of the data is 2.2

Read more about variance at:

brainly.com/question/15858152

4 0
2 years ago
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